Physics
Forces, Energy and Machines
281 Questions
Forces, energy, and machines are fundamental physics concepts focusing on mechanics, work, power, and simple machines. These topics regularly appear in general science sections of competitive exams. Use these questions to practice calculating resultant forces, mechanical advantage, and work done in various scenarios.
Resultant force calculationsMechanical advantage of leversWork and power equationsApparent weight in elevatorsBending moments
Forces, Energy and Machines Questions
A 10 kg object is lifted vertically at a constant speed of 2 m/s through a height of 5 meters. How much work is done?
A
Correct answer
Explanation
Work done = Force × Displacement = (10 kg × 9.8 m/s²) × 5 m = 100 J.
A 100 kg object is at rest on a horizontal surface. A force of 50 N is applied to the object for 10 seconds. What is the work done on the object?
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500 J
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1000 J
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1500 J
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2000 J
A
Correct answer
Explanation
Work done = Force × Displacement = 50 N × 0 m = 0 J.
The formula for calculating the force required to move a vehicle is:
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Force = Mass * Acceleration
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Force = Mass / Acceleration
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Force = Acceleration / Mass
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Force = Mass * Velocity
A
Correct answer
Explanation
The force required to move a vehicle is calculated by multiplying the mass of the vehicle by its acceleration.
The formula for calculating the work done by a vehicle is:
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Work = Force * Distance
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Work = Force / Distance
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Work = Force + Distance
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Work = Force - Distance
A
Correct answer
Explanation
The work done by a vehicle is calculated by multiplying the force applied to the vehicle by the distance over which the force is applied.
What is the relationship between the joint torques and the generalized forces in the Euler-Lagrange equations?
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Joint torques are equal to the generalized forces
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Joint torques are proportional to the generalized forces
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Joint torques are the derivatives of the generalized forces
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Joint torques are the integrals of the generalized forces
B
Correct answer
Explanation
In the Euler-Lagrange equations, the joint torques are proportional to the generalized forces, with the proportionality constant being the partial derivative of the Lagrangian with respect to the corresponding joint variable.
What is the formula for calculating the work done by a constant force?
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$W = Fd$
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$W = F/d$
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$W = F \cdot d$
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$W = F \cdot d^2$
C
Correct answer
Explanation
The formula for calculating the work done by a constant force is $W = F \cdot d$, where $W$ is the work done, $F$ is the force applied, and $d$ is the displacement of the object in the direction of the force.
In a game, a player character is standing on a platform that is 10 meters above the ground. The player character jumps off the platform and lands on the ground. What is the work done by gravity on the player character?
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1000 J
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2000 J
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3000 J
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4000 J
A
Correct answer
Explanation
The work done by gravity on the player character can be calculated using the equation: W = Fd, where W is the work done, F is the force of gravity (mg), and d is the distance traveled (10 meters). Assuming that the player character has a mass of 100 kg, the force of gravity is 100 kg * 9.8 m/s^2 = 980 N. Plugging in the values, we get: W = 980 N * 10 meters = 9800 J.
In a game, a player character is standing on a platform that is 10 meters above the ground. The player character jumps off the platform and lands on the ground. What is the power exerted by the player character during the jump?
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1000 W
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2000 W
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3000 W
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4000 W
B
Correct answer
Explanation
The power exerted by the player character during the jump can be calculated using the equation: P = W / t, where P is the power, W is the work done, and t is the time taken. Assuming that the player character takes 1 second to jump, the power exerted by the player character is 1000 J / 1 s = 1000 W.
Which of the following integrals represents the work done by a force (F(x) = 3x^2 - 2x + 1) in moving an object from (x = 0) to (x = 2)?
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\(\int_0^2 (3x^2 - 2x + 1) dx\)
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\(\int_0^2 (3x^2 - 2x + 1) dx\)
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\(\int_0^2 (3x^2 - 2x + 1)^2 dx\)
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\(\int_0^2 (3x^2 - 2x + 1)^3 dx\)
A,B
Correct answer
Explanation
To find the work done by a force (F(x)) in moving an object from (x = a) to (x = b), we need to use the formula (W = \int_a^b F(x) dx). In this case, (F(x) = 3x^2 - 2x + 1) and ([a, b] = [0, 2]).
What is the maximum weight that a robot is allowed to lift?
C
Correct answer
Explanation
The maximum weight that a robot is allowed to lift is 150 kg.
An object moves from a position of -5 meters to a position of 10 meters. What is the total displacement of the object?
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5 meters
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10 meters
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15 meters
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20 meters
C
Correct answer
Explanation
The total displacement of the object is the change in its position, which is calculated by subtracting the initial position from the final position. In this case, the total displacement is 10 meters - (-5 meters) = 15 meters.