Physics

Fluid Mechanics and Hydraulics

361 Questions

Fluid mechanics and hydraulics questions address the principles of fluid flow, pipe resistance, and open channel dynamics. The topics include Bernoulli equation, Navier-Stokes equation, and hydrograph calculations. These concepts are crucial for civil and mechanical engineering competitive examinations.

Fluid flow equationsOpen channel flowPipe frictionHydraulic jumpHydrograph analysis

Fluid Mechanics and Hydraulics Questions

Multiple choice
  1. 10 mm

  2. 16 mm

  3. 20 mm

  4. 23 mm

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total rainfall = 9 + 28 + 12 + 7 = 56 mm. Phi index = 10 mm/h. Runoff occurs when rainfall > phi. Hours 1, 2, 3, 4 have rainfall 9, 28, 12, 7. Rainfall > 10 occurs in hours 2 (28-10=18) and 3 (12-10=2). Total runoff = 18 + 2 = 20 mm.

Multiple choice
  1. 5.6 N/m2

  2. 10.8 N/m2

  3. 12.3 N/m2

  4. 17.2 N/m2

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

 $\tau = \omega RS_0, \text{Now}, S_0 = 0.0042\\ R = y/2 = \frac{0.836}{2} = 0.418 \\ \therefore \tau = 9810 \times 0.418 /times 0.0042 \\ \hspace{0.8cm} = 17.22 N/m^2$

Multiple choice
  1. 11.8 x 10–3 mm

  2. 16.0 x 10–3 mm

  3. 50 x 10–3 mm

  4. 58 x 10–3 mm

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

 

Multiple choice
  1. attenuated peak with reduced time-base

  2. attenuated peak with increased time-base

  3. increased peak with increased time-base

  4. increased peak with reduced time-base

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

 Main function of any reservoir in the flood routing is to reduce the peak and increase the time base so that there will be less damage on the downstream of flow.

Multiple choice
  1. 6.48 m

  2. 5.24 m

  3. 3.24 m

  4. 2.24 m

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Using the hydraulic jump formula: y2 = (-y1 / 2) + sqrt((y1^2 / 4) + (2 * v1^2 * y1 / g)). Given v1 = 13.72, y1 = 0.3, g = 9.81. Froude number Fr = 13.72 / sqrt(9.81 * 0.3) = 13.72 / 1.716 = 7.99. y2 = 0.3/2 * (sqrt(1 + 8 * 7.99^2) - 1) = 0.15 * (sqrt(1 + 510.7) - 1) = 0.15 * (22.6 - 1) = 3.24 m.