Physics

Electromagnetic Waves and Spectrum

659 Questions

Electromagnetic waves and spectrum questions test a candidate's understanding of radiation frequencies, wavelengths, and the properties of different rays like infrared, ultraviolet, and visible light. Concepts also cover practical applications in astronomy and the fundamental speed of light calculations. This physics topic appears regularly in general science sections of major competitive examinations.

UV rays propertiesElectromagnetic radiation frequencyWavelength identificationSpeed of light calculationsBlack body radiation

Electromagnetic Waves and Spectrum Questions

Multiple choice
  1. E2 = E1

  2. 4$\widehat a$x + 0.75$\widehat a$y + 1.2 5$\widehat a$z
  3. 3$\widehat a$x + 3$\widehat a$y + 5$\widehat a$z
  4. - 3$\widehat a$x + 3$\widehat a$y + 5$\widehat a$z
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Multiple choice
  1. 2 cos $\left( \dfrac{2\pi s}{\lambda} \right)$
  2. 2 sin $\left( \dfrac{2\pi s}{\lambda} \right)$
  3. 2 cos $\left( \dfrac{\pi s}{\lambda} \right)$
  4. 2 sin $\left( \dfrac{\pi s}{\lambda} \right)$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Multiple choice
  1. Probability of symbol error for constellation 1 is lower.

  2. Probability of symbol error for constellation 1 is higher.

  3. Probability of symbol error is equal for both the constellations.

  4. The value of 0 N will determine which of the two constellations has a lower probability of symbol error.

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Noise power is same for both which is $\dfrac{N_0}{2}$

Thus probability of error will be lower for the constellation 1 as it has higher signal energy.

Multiple choice
  1. 4a2

  2. 3.5

  3. 2

  4. 8

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

By using solution we get                        Energy of constellation 1 = 14 a^2                      Energy of constellation 2 = 4 a^2                                                  Ratio = 14 a^2/4 a^2 = 3.5                      

Multiple choice
  1. 2$\pi$ m2
  2. $\pi$2 m2
  3. $\frac{\pi}{2}$ m2
  4. $\pi$m2
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Multiple choice
  1. Re $(\overrightarrow{P})$ remains constant at any radial distance from the source
  2. Re $(\overrightarrow{P})$ increases with increasing radial distance from the source
  3. _ $∯_s Re$$(\overrightarrow{P})$.$\hat{n}$dS remains constant at any radial distance from the source
  4. $∯_s Re$$(\overrightarrow{P})$.$\hat{n}$dS decreases with increasing radial distance form the source
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Powe radiated from any source is constant.