Mathematics
Coordinate Geometry and Graphs
77 Questions
Coordinate geometry involves plotting linear equations, analyzing graphical data, and understanding planar graphs using vertices, edges, and faces. These concepts are essential for calculating intersection points and interpreting graphical information. Such questions frequently appear in engineering, state, and civil services examinations.
Euler graph formulaLinear equation graphsGraph intersection pointsBar graphsLinear functionsTangent equations
Coordinate Geometry and Graphs Questions
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f=v-e+2
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f=e-v+2
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f=e+v-2
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f=e-v-2
B
Correct answer
Explanation
Euler's formula for connected planar graphs states v - e + f = 2, where v is vertices, e is edges, and f is faces. Rearranging gives f = e - v + 2. This fundamental relationship applies to all connected planar graphs drawn without edge crossings.
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f=v-e+2
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f=e-v+2
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f=e+v-2
-
f=e-v-2
B
Correct answer
Explanation
Euler's formula for connected planar graphs states v - e + f = 2, where v is vertices, e is edges, and f is faces. Rearranging gives f = e - v + 2. This fundamental relationship applies to all connected planar graphs drawn without edge crossings.
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a = 2, b = 8
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a = 4, b = 6
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a = 6, b = 4
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a = 8, b = 2
C
Correct answer
Explanation
Using the line equation (x-5)/(0-5) = (y-1)/(17/2-1) = (z-a)/(-13/2-a). For x=3: (3-5)/-5 = 2/5. Then (b-1)/(15/2) = 2/5 => b-1=3 => b=4. And (1-a)/(-13/2-a) = 2/5 => 5-5a = -13-2a => 18=3a => a=6.
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$\mid$S$\mid$ = 2$\mid$T$\mid$
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$\mid$S$\mid$ = $\mid$T$\mid$ - 1
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$\mid$S$\mid$ = $\mid$T$\mid$
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$\mid$S$\mid$ = $\mid$T$\mid$ + 1
C
Correct answer
Explanation
By the given condition, S and T are two different trees.
$\xi(S) = \xi(T)$
So, both S and T have the same number of vertices. Thus,
|S| = |T|
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x2 + y2 + 2x - 2y = 0
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x2 + y2 - 2x - 2y = 0
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x2 + y2 - 2x + 2y = 0
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x2 + y2 + 2x + 2y = 0
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x2 + y2 - 4x - 4y = 0
B
Correct answer
Explanation
Let the coordinates of the third vertex be (x,y).
Applying the Pythagoras theorem in the right angled triangle, we get
8 = (x-2)2 + y2 + x2 + (y-2)2
8 = x2+4-4x+y2+x2+y2+4-4y
Cancelling 8, we get
x2+y2-2x-2y=0 (Correct Answer)
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(11, –6)
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(–6, 11)
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(11, 6)
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(–11, 6)
A
Correct answer
Explanation
Since ordered pair is written in the order (x, y), where x = x coordinate of that point and y = y coordinate of that point, so the ordered pair for point D is (11, –6).
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(11, – 3)
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(3, 11)
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(– 11, – 3)
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(11, 3)
D
Correct answer
Explanation
Because ordered pair representing any point is written as (x, y), where x = x-coordinate of that point and y = y-coordinate of that point.
$\therefore$ The ordered pair representing the point E is (11, 3).
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(3, 0)
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(0, 3)
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(– 3, 0)
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(0, – 3)
B
Correct answer
Explanation
The point B lies on y-axis; so the x-coordinate must be zero and y-coordinate must be 3.
Thus, the ordered pair representing the point B is (0, 3).
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(–8, –7)
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(7, –8)
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(8, –7)
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(–8, 7)
D
Correct answer
Explanation
(–8, 7) represents point A on the graph.
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(10, 8)
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(– 10, – 8)
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(– 8, – 10)
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(8, 10)
B
Correct answer
Explanation
The ordered pair representing C is (– 10, – 8) as the ordered pairs are written in the order (x, y),
where x = x-coordinate of the point and y = y-coordinate of the point.
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(– 12, 5)
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(5, – 12)
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(5, 12)
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(– 5, 12)
B
Correct answer
Explanation
The ordered pair representing point H is (5, – 12) as ordered pairs are written in the order (x, y),
where x = x-coordinate of the point and y = y-coordinate of the point.
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(3, 13)
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(13, 3)
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(– 3, – 13)
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(– 3, 13)
A
Correct answer
Explanation
As the ordered pair representing a point is written as (x, y), where x = x-coordinate of the point and y = y-coordinate of the point.
Then, the ordered pair representing I is (3, 13).
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(10, - 6)
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(6, - 10)
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(- 6, 10)
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(6, 10)
C
Correct answer
Explanation
As the ordered pair for any point is written in the form (x, y), where x = x co-ordinate of the point and y = y co-ordinate of the point.
Then, the ordered pair representing F is given by (- 6, 10).
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(6, 6)
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(6, - 6)
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(- 6, 6)
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(- 6, - 6)
A
Correct answer
Explanation
As the ordered pair representing any point is given by (x, y), where x = x co-ordinate of the point and y = y co-ordinate of the point.
Then, the ordered pair representing J is given by (6, 6).