Physics ยท Science General
Collisions, Momentum and Kinetic Energy
385 Questions
Collisions, momentum, and kinetic energy questions analyze the principles of elastic and inelastic impacts. They require calculating mass, velocity, and conserved energy during physical interactions. These foundational physics topics are essential for most government engineering and general science examinations.
Elastic collisionsInelastic collisionsMomentum calculationKinetic energy principlesVelocity after impact
Collisions, Momentum and Kinetic Energy Questions
A 20 kg object is moving at a velocity of 10 m/s. What is its kinetic energy?
C
Correct answer
Explanation
The kinetic energy of the object is given by the formula $K = rac{1}{2}mv^2$. Substituting the values of $m$ and $v$, we get $K = rac{1}{2}(20 kg)(10 m/s)^2 = 800 J$.
A 30 kg object is moving at a velocity of 15 m/s. What is its kinetic energy?
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675 J
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1350 J
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2700 J
-
5400 J
B
Correct answer
Explanation
The kinetic energy of the object is given by the formula $K = rac{1}{2}mv^2$. Substituting the values of $m$ and $v$, we get $K = rac{1}{2}(30 kg)(15 m/s)^2 = 1350 J$.
A 40 kg object is moving at a velocity of 20 m/s. What is its kinetic energy?
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1600 J
-
3200 J
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6400 J
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12800 J
B
Correct answer
Explanation
The kinetic energy of the object is given by the formula $K = rac{1}{2}mv^2$. Substituting the values of $m$ and $v$, we get $K = rac{1}{2}(40 kg)(20 m/s)^2 = 3200 J$.
A 50 kg object is moving at a velocity of 25 m/s. What is its kinetic energy?
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3125 J
-
6250 J
-
12500 J
-
25000 J
B
Correct answer
Explanation
The kinetic energy of the object is given by the formula $K = rac{1}{2}mv^2$. Substituting the values of $m$ and $v$, we get $K = rac{1}{2}(50 kg)(25 m/s)^2 = 6250 J$.
A 100 kg object is moving at a velocity of 30 m/s. What is its kinetic energy?
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15000 J
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30000 J
-
60000 J
-
120000 J
Correct answer
Explanation
The kinetic energy of the object is given by the formula $K = rac{1}{2}mv^2$. Substituting the values of $m$ and $v$, we get $K = rac{1}{2}(100 kg)(30 m/s)^2 = 45000 J$.
A 200 kg object is moving at a velocity of 40 m/s. What is its kinetic energy?
-
32000 J
-
64000 J
-
128000 J
-
256000 J
C
Correct answer
Explanation
The kinetic energy of the object is given by the formula $K = rac{1}{2}mv^2$. Substituting the values of $m$ and $v$, we get $K = rac{1}{2}(200 kg)(40 m/s)^2 = 128000 J$.
A 300 kg object is moving at a velocity of 50 m/s. What is its kinetic energy?
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225000 J
-
450000 J
-
900000 J
-
1800000 J
B
Correct answer
Explanation
The kinetic energy of the object is given by the formula $K = rac{1}{2}mv^2$. Substituting the values of $m$ and $v$, we get $K = rac{1}{2}(300 kg)(50 m/s)^2 = 450000 J$.
A 400 kg object is moving at a velocity of 60 m/s. What is its kinetic energy?
-
720000 J
-
1440000 J
-
2880000 J
-
5760000 J
B
Correct answer
Explanation
The kinetic energy of the object is given by the formula $K = rac{1}{2}mv^2$. Substituting the values of $m$ and $v$, we get $K = rac{1}{2}(400 kg)(60 m/s)^2 = 1440000 J$.
A 500 kg object is moving at a velocity of 70 m/s. What is its kinetic energy?
-
1225000 J
-
2450000 J
-
4900000 J
-
9800000 J
B
Correct answer
Explanation
The kinetic energy of the object is given by the formula $K = rac{1}{2}mv^2$. Substituting the values of $m$ and $v$, we get $K = rac{1}{2}(500 kg)(70 m/s)^2 = 2450000 J$.
Which of the following is a common approach for resolving collisions between objects in a physics simulation?
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Impulse-based collision response
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Penalty-based collision response
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Position-based collision response
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Energy-based collision response
A
Correct answer
Explanation
Impulse-based collision response is a common approach that involves applying an impulse to objects at the moment of collision to conserve momentum.