Quantitative Aptitude
Boats and Streams
369 Questions
Boats and Streams Questions
-
$6$ km/hr
-
$5$ km/hr
-
$3.5$ km/hr
-
$4.5$ km/hr
A
Correct answer
Explanation
Let v be the stream speed. Upstream speed is 18-v, downstream is 18+v. Time difference is 24/(18-v) - 24/(18+v) = 1. Solving 24(18+v - 18+v) / (324 - v^2) = 1 gives 48v = 324 - v^2, or v^2 + 48v - 324 = 0. Factoring (v+54)(v-6) = 0 gives v = 6.
-
$2 hrs$
-
$1 hr$
-
$\dfrac{4}{3} hrs$
-
None of the above
C
Correct answer
Explanation
Upstream speed = 4 - 2 = 2 km/h. Downstream speed = 4 + 2 = 6 km/h. Time upstream = 2 km / 2 km/h = 1 hour. Time downstream = 2 km / 6 km/h = 1/3 hour. Total time = 1 + 1/3 = 4/3 hours.
B
Correct answer
Explanation
Upstream speed = 11-x, downstream = 11+x. Time = 12/(11-x) + 12/(11+x) = 11/4. Solving for x: 12(11+x+11-x)/(121-x^2) = 11/4. 12(22)/(121-x^2) = 11/4. 264/(121-x^2) = 11/4. 24/(121-x^2) = 1/4. 96 = 121-x^2. x^2 = 25, x = 5.
-
$5$ km / hr
-
$8$ km/ hr
-
$10$ km/hr
-
$15$ km/hr
A
Correct answer
Explanation
Let stream speed be s. Time = 30/(15-s) + 30/(15+s) = 4.5. 30(15+s+15-s)/(225-s^2) = 4.5. 900/4.5 = 225-s^2. 200 = 225-s^2. s^2 = 25, s = 5.
-
9 km/hr
-
7 km/hr
-
5 km/hr
-
3 km/hr
C
Correct answer
Explanation
Let stream speed be s. Downstream speed = 15 + s, upstream speed = 15 - s. Total time = 40 / (15 + s) + 40 / (15 - s) = 6. 40 * (15 - s + 15 + s) / (225 - s^2) = 6. 40 * 30 / (225 - s^2) = 6. 1200 / (225 - s^2) = 6. 200 = 225 - s^2. s^2 = 25, so s = 5.
-
$12$ km/hr
-
$9$ km/hr
-
$5$ km/hr
-
$3$ km/hr
C
Correct answer
Explanation
Let the stream speed be x. The downstream speed is 15+x and upstream is 15-x. The total time is 30/(15+x) + 30/(15-x) = 4.5. Solving this quadratic equation 30(15-x + 15+x) / (225-x^2) = 4.5 leads to 900 / (225-x^2) = 4.5, so 225-x^2 = 200, x^2 = 25, x = 5.
-
4 k.ms/hr
-
1 k.ms/hr
-
2 k.ms/hr
-
15 k.ms/hr
-
$\dfrac{5}{4}$
-
$\dfrac{1}{5}$
-
$\dfrac{8}{9}$
-
$\dfrac{7}{8}$
C
Correct answer
Explanation
Let distance be d. Downstream speed = 15 + 5 = 20. Upstream speed = 15 - 5 = 10. Average speed = 2 * 20 * 10 / (20 + 10) = 400 / 30 = 40/3. Ratio to speed in still water (15) = (40/3) / 15 = 40/45 = 8/9.
-
$9$ km/hr
-
$5$ km/hr
-
$2$ km/hr
-
none of these
C
Correct answer
Explanation
Let speed of stream be s. Upstream speed = 5-s, downstream speed = 5+s. Time difference: 5.25/(5-s) - 5.25/(5+s) = 1. 5.25 * (5+s - (5-s)) / (25-s^2) = 1. 5.25 * 2s = 25-s^2. 10.5s = 25-s^2. s^2 + 10.5s - 25 = 0. Using quadratic formula: s = (-10.5 + sqrt(110.25 + 100)) / 2 = (-10.5 + 14.5) / 2 = 2.
-
$3\ km/h$
-
$6\ km/h$
-
$10\ km/h$
-
$12\ km/h$
A
Correct answer
Explanation
Speed downstream = 1 km / (5/60) h = 12 km/h. Speed upstream = 6 km / 1 h = 6 km/h. Speed of stream = (Downstream - Upstream) / 2 = (12 - 6) / 2 = 3 km/h.
-
$2.5$ km/hr
-
$1.5$ km/hr
-
$3.4$ km/hr
-
$5.4$ km/hr
A
Correct answer
Explanation
Upstream speed = distance / time = 37.5 / 5 = 7.5 km/hr. Upstream speed = boat speed - stream speed. 7.5 = 10 - stream speed, so stream speed = 2.5 km/hr.
-
$2.5$ km
-
$3$ km
-
$2.4$ km
-
$3.6$ km
C
Correct answer
Explanation
Let distance be d. Downstream speed = 5+1 = 6 km/hr. Upstream speed = 5-1 = 4 km/hr. Total time = d/6 + d/4 = 1 => (2d+3d)/12 = 1 => 5d = 12 => d = 2.4 km.
C
Correct answer
Explanation
Downstream speed = 1 km / (6/60) hr = 10 km/hr. Upstream speed = 1 km / (10/60) hr = 6 km/hr. Current speed = (Downstream - Upstream) / 2 = (10 - 6) / 2 = 2 km/hr.
-
$5$ hours $50$ min
-
$6$ hours
-
$6$ hours $50$ min
-
$12$ hours $10$ min
C
Correct answer
Explanation
Let boat speed = 36x, current = 5x. Downstream speed = 41x, upstream = 31x. Time downstream = 5h 10m = 310 min. Distance = 41x * 310. Time upstream = Distance / 31x = (41x * 310) / 31x = 41 * 10 = 410 min. 410 min = 6 hours 50 min.
-
$1 : 5$
-
$1 : 3$
-
$5 : 1$
-
$2 : 3$
C
Correct answer
Explanation
Let b be boat speed and c be current speed. Downstream speed is b+c, upstream is b-c. Given 2(b+c) = 3(b-c), so 2b + 2c = 3b - 3c, which simplifies to b = 5c. The ratio b:c is 5:1.