Quantitative Aptitude

Averages

1,527 Questions
All Basic average and reverse calculation 405 Adding or removing an observation 342 Weighted and combined averages 320 Replacement and correction of a recorded value 233 Ratio shortcut for two-group mixtures 111 Equal-distance average speed 59 Age, score, weight, and spending applications 32 Consecutive terms and arithmetic progressions 25

Averages Questions

Multiple choice

The average marks obtained by a group of 45 students were 16.2. One student left the group as a result of which the average of the remaining students rose to 16.5. But another student came in as a result of which the average marks of the group dropped a bit and became 16.4. What were the average marks obtained by the student who left and the one who joined?

  1. 7.5

  2. 12.5

  3. 15

  4. 16.5

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Sum of 45 = 45 * 16.2 = 729. One leaves: Sum = 729 - x = 44 * 16.5 = 726. So x = 3. One joins: Sum = 726 + y = 45 * 16.4 = 738. So y = 12. Average of x and y = (3 + 12) / 2 = 7.5.

Multiple choice

Passage

Directions: In the table below, the numbers of students studying in different standards of six different schools are given. Study the table carefully to answer the question that follows. Standards → Schools ↓ I II III IV V VI A 42 54 48 58 50 38 B 50 60 58 45 45 46 C 40 48 58 46 42 54 D 45 55 46 40 52 50 E 48 55 44 55 52 48 F 52 52 54 42 60 54

What is the approximate average number of students studying in standard I in all the schools?

  1. 38

  2. 50

  3. 40

  4. 46

  5. 43
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Sum the students in standard I for all schools: 42 (A) + 50 (B) + 40 (C) + 45 (D) + 48 (E) + 52 (F) = 277. Dividing the total 277 by 6 schools gives approximately 46.16, which rounds to 46.

Multiple choice

Passage

Directions: The table given below shows the number of students who were absent and the percentage of students who were present in the two given examinations from five different schools. The table also shows the percentage of students who were present in the Biology and Physics examinations. School Absent Present (in %) Biology (in %) Physics (in %) K 83,300 65 32 68 L 1,01,520 60 29 71 M 1,13,520 40 30 70 N 60,830 65 42 58 O 24,003 55 25 75

What is the average of the number of the students who were present in Physics examination from schools N, K and L?

  1. 92,946

  2. 84,632

  3. 9,74,365

  4. 4,67,894
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

First, calculate the number of students present for each school: K (83,300 absent, 65% present means 83,300 is 35% of total, so total is 238,000; present is 154,700), L (1,01,520 absent, 60% present means 1,01,520 is 40% of total, so total is 253,800; present is 152,280), N (60,830 absent, 65% present means 60,830 is 35% of total, so total is 173,800; present is 112,970). Next, find the number of students present in Physics: K (68% of 154,700 = 105,196), L (71% of 152,280 = 108,118.8), N (58% of 112,970 = 65,522.6). The average is (105,196 + 108,118.8 + 65,522.6) / 3 = 92,945.8, which rounds to 92,946.

Multiple choice

Passage

Directions : Read the following information and answer the given question. Mr. Joey owns a wholesale shop at which he deals with pairs of shoes, where he buys and sells pairs of shoes every day. The first table below presents his average selling price per pair of shoes and his average cost price per pair of shoes for eight years, from 2009 to 2016. The second table provides the profit (in $ '000) that he earned in each year. Year 2009 2010 2011 2012 2013 2014 2015 2016 Average Selling Price per Pair (in $) 47 43 49 43 47 42.50 48 51 Average Cost Price per Pair (in $) 42.50 41.50 47.50 40.50 43.50 41 44.50 47.50 year 2009 2010 2011 2012 2013 2014 2015 2016 Profit ($ '000) 756 234 285 410 616 270 658 616

What is the average number of pairs of shoes that Mr. Joey sold per year during the given period?

  1. 1,76,000

  2. 1,75,250

  3. 1,74,750

  4. 1,73,250

  5. 1,72,250
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Profit = (Selling Price - Cost Price) * Quantity. Quantity = Profit / (Selling Price - Cost Price). Calculate for each year: 2009: 756/(47-42.5) = 168; 2010: 234/(43-41.5) = 156; 2011: 285/(49-47.5) = 190; 2012: 410/(43-40.5) = 164; 2013: 616/(47-43.5) = 176; 2014: 270/(42.5-41) = 180; 2015: 658/(48-44.5) = 188; 2016: 616/(51-47.5) = 176. Average = (168+156+190+164+176+180+188+176)/8 = 1398/8 = 174.75. In thousands, this is 1,74,750.

Multiple choice

Passage

Directions: Study the following information carefully and answer the question that follows. This table below shows the number of people who booked their tickets for watching a movie in three different cinemas A, B and C in a particular week. Days A B C Monday 89 98 45 Tuesday 72 84 53 Wednesday 64 72 60 Thursday 77 65 68 Friday 105 102 110 Saturday 120 124 105 Sunday 123 128 98

What was the average number of people who booked the tickets for C for the whole week together?

  1. 81

  2. 79

  3. 78

  4. 77

  5. 75
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Sum the bookings for C: 45 + 53 + 60 + 68 + 110 + 105 + 98 = 539. The average is 539 / 7 = 77.

Multiple choice

Passage

Directions: Following table shows the marks scored by six students in different subjects. Read the table and answer the question based on this table. Student Subject Maths (150) Hindi (120) English (100) Physics (100) Chemistry (50) GK (80) A 85 65 70 65 35 40 B 70 80 63 68 49 30 C 32 60 40 80 50 35 D 140 104 65 48 60 18 E 123 79 79 84 40 27 F 57 106 68 66 48 44

What is the average of marks obtained by all the students in Physics?

  1. 68.5

  2. 74.5

  3. 75

  4. 76.5
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Physics marks: A=65, B=68, C=80, D=48, E=84, F=66. Sum = 411. Average = 411 / 6 = 68.5.

Multiple choice

Passage

Directions: Following table shows the marks scored by six students in different subjects. Read the table and answer the question based on this table. Student Subject Maths (150) Hindi (120) English (100) Physics (100) Chemistry (50) GK (80) A 85 65 70 65 35 40 B 70 80 63 68 49 30 C 32 60 40 80 50 35 D 140 104 65 48 60 18 E 123 79 79 84 40 27 F 57 106 68 66 48 44

What is the average percentage of marks obtained by all the students in Maths?

  1. 56%

  2. 65%

  3. 68%

  4. 70%
Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice

Passage

Directions: S tudy the data carefully and answer the question. The table given below shows data related to the number of children and adults (males : females) who joined swimming classes. Swimming Class Number of Children Number of Adults (Males : Females) A 42 3 : 4 B 56 1 : 5 C 28 3 : 5 D 0 3 : 7 E 70 2 : 3 F 14 4 : 5 Total 140 people joined each swimming class.

Find the approximate average number of adult males who joined swimming classes A, D and E together.

  1. 37

  2. 53

  3. 68

  4. 79

  5. 89
Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice

Passage

Directions: Study the following information carefully and answer the question that follows. The pie chart given below gives information about the institutes preferred by bank exam aspirants of east region for online test series course for preparation of bank exams. Total number of bank aspirants = 4,80,000 (Assume no bank exam aspirant enrolls for online test series course of more than 1 institute and there is only single package available in each institute for online test series.)

Directions: The table below gives the online test series package charges of each institute: | Institute | Online test series charges | | --- | --- | | BG | Rs. 235 | | CI | Rs. 365 | | TS | Rs. 159 | | BM | Rs. 187 | | EL | Rs. 557 | If a student buys online package of CI providing 7 mocks and online test series package of BM providing 5 mocks, then what is the average price paid per mock by the student?

  1. Rs. 39

  2. Rs. 43

  3. Rs. 46

  4. None of these

  5. Can't be determined
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

CI package: 365 Rs for 7 mocks. BM package: 187 Rs for 5 mocks. Total cost = 365 + 187 = 552 Rs. Total mocks = 7 + 5 = 12. Average price per mock = 552 / 12 = 46 Rs.

Multiple choice

Passage

Directions: Study the following pie chart carefully and answer the question given below it. The pie chart below shows the number of people working in Ludhiana, in various professions. (Total number of people = 40 , 000 ) Number of women in different professions: Profession Percentage Engineer 23% Teacher 65% Lawyer 38% Dietician 76% Firefighter 54% Journalist 18%

What is the average number of women in all the professions together?

  1. 2890

  2. 3890

  3. 4890

  4. 5890

  5. 6890
Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice

Passage

Directions: Study the given information and answer the following question. In the table given below, marks obtained by different students in different subjects are listed: Subjects (Maximum Marks) → Students ↓ Hindi (100) English (100) Maths (100) Social Studies (100) Science (75) Sanskrit (50) Physical Education (75) Anupama 85 95 87 87 65 35 71 Bhaskar 72 97 35 77 62 41 64 Charu 64 78 74 63 55 25 53 Deepak 65 62 69 81 70 40 50 Garima 92 82 81 79 49 30 61 Vishal 55 70 65 69 44 28 30

Calculate the average marks obtained by all the students combined in Science.

  1. 55.75

  2. 57.5

  3. 60

  4. 59.5

  5. 58
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The marks in Science for the six students are 65, 62, 55, 70, 49, 44. The sum is 345. The average is 345 / 6 = 57.5.

Multiple choice

Passage

Directions: Study the following table carefully to answer the question. Percentage of Marks Obtained by Six Students in Different Subjects Subject Student History (75) Geography (80) Maths (120) Science (150) English (75) Hindi (50) A 80 85 89 79 69 76 B 74 79 92 84 72 67 C 86 65 76 82 82 87 D 69 72 62 90 78 68 E 64 64 75 86 65 62 F 76 82 95 78 60 73 NOTE: Figures in bracket indicate the maximum marks assigned for the subjects.

What are the percentage average marks obtained by the six students in Geography?

  1. 74.5

  2. 75.4

  3. 59.6

  4. 58.9

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice

Passage

Directions: Read the following information and answer the given question. A doctor wanted to know the weight of 5 boys, each weighing less than 55 kg(Consider all the weights are natural numbers). The children would not let the doctor measure their weights on the weighing machine unless they were weighed in pairs. The weights (in kg) thus obtained were: 90, 92, 93, 94, 95, 96, 97, 98, 100 and 101. The names of the 5 children were Tinu, Minu, Chinu, Tipu and Tilu. Also, their weights were in the order Tilu > Tipu > Tinu > Minu > Chinu. The total weight of Tilu and Tipu is 101 kg, that of Minu and Chinu is 90 kg, and that of Tinu and Chinu is 92 kg.

What is the average weight of Tipu and Tinu?

  1. 48.1 kg

  2. 48.5 kg

  3. 49.5 kg

  4. 54.5 kg
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the weights be c < m < t < tp < tl. Given equations: m+c=90, t+c=92, tl+tp=101. Using the given sums and the ordering constraint, we can solve for individual weights. The average of Tipu and Tinu is (tp+t)/2 = 97/2 = 48.5.

Multiple choice

Passage

Directions: Study the following information and answer the question that follows. The table given below shows the marks obtained by six students in three subjects. Student Marks (Out of 100) English Hindi Mathematics A 85 65 93 B 90 76 99 C 92 78 100 D 67 89 96 E 89 92 95 F 81 93 98

What are the average marks per student in Mathematics?

  1. 93.33

  2. 96.83

  3. 95.33

  4. 94.33
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

To find the average marks in Mathematics, sum the marks of all six students: 93 + 99 + 100 + 96 + 95 + 98 = 581. Dividing this total by the number of students (6) gives approximately 96.83.

Multiple choice

Passage

Directions: Study the following information and answer the question that follows. The table given below shows the marks obtained by six students in three subjects. Student Marks (Out of 100) English Hindi Mathematics A 85 65 93 B 90 76 99 C 92 78 100 D 67 89 96 E 89 92 95 F 81 93 98

What are the average marks per subject scored by D?

  1. 82.5

  2. 87.5

  3. 84

  4. 88
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Marks for D: English 67, Hindi 89, Mathematics 96. Sum = 67 + 89 + 96 = 252. Average = 252 / 3 = 84.