Averages Questions

Multiple choice
  1. 100

  2. 110

  3. 120

  4. 150

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let x be the number of passed candidates. Then 120 - x is the number of failed candidates. Total marks = 120 * 35 = 4200. Sum of marks = 39x + 15(120 - x) = 4200. 39x + 1800 - 15x = 4200. 24x = 2400. x = 100.

Multiple choice
  1. $20$
  2. $22$
  3. $25$
  4. $27$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total sum of 8 numbers = 8 * 20 = 160. Sum of first two = 2 * 15.5 = 31. Sum of next three = 3 * 21.33 = 64. Sum of remaining three (6th, 7th, 8th) = 160 - 31 - 64 = 65. Let 6th number be x. Then 7th is x+4 and 8th is x+7. x + (x+4) + (x+7) = 65 => 3x + 11 = 65 => 3x = 54 => x = 18. The 8th number is x + 7 = 18 + 7 = 25.

Multiple choice
  1. $90$
  2. $88$
  3. $82$
  4. $80$
  5. 79

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Total points needed for 8 tests = 8 * 80 = 640. Current points = 5 * 78 = 390. Points needed for remaining 3 tests = 640 - 390 = 250. This question implies the 6th test is the only one left to reach the average, but it asks for the 6th test specifically. If he needs to reach 80 average after 6 tests, he needs 6 * 80 = 480 total. 480 - 390 = 90.

Multiple choice
  1. None

  2. One

  3. Two

  4. Three

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total sum of 5 scores = 5 * 80 = 400. To maximize the number of 50s, minimize the other scores. Let x be the number of 50s. The remaining (5-x) scores must be as high as possible (100). 50x + 100(5-x) >= 400. 50x + 500 - 100x >= 400, so 100 >= 50x, x <= 2. The maximum is 2.

Multiple choice
  1. $45$
  2. $50$
  3. $51.4$ approx
  4. $54.6$ approx
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let total students be 100. Total score = 5200. Brightest 20: 20 * 80 = 1600. Dullest 25: 25 * 31 = 775. Remaining 55: 5200 - 1600 - 775 = 2825. Average = 2825 / 55 = 51.36.

Multiple choice
  1. $1$
  2. $2$
  3. $3$
  4. $4$
  5. $5$
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Initial: 10 fruits, avg 56 cents, total 560 cents. Let a be apples, o be oranges. 40a + 60o = 560 and a + o = 10. Solving gives a=2, o=8. New average 52 cents for k fruits: (40a' + 60o') / k = 52. Since a' + o' = k, 40a' + 60o' = 52a' + 52o' => 8o' = 12a' => 2o' = 3a'. If k=5, a'=2, o'=3. Original had 8 oranges, now 3, so 5 must be put back.