Mathematics · Reasoning
Algebraic Expressions
157 Questions
Algebraic expressions form the foundation of mathematics, involving variables, constants, and arithmetic operations. This topic includes evaluating coefficients, solving proportional relationships, and understanding boolean logic. It is widely tested across various competitive exams to assess analytical skills.
Variable evaluationExpression coefficientsBoolean logic variablesDirect proportionalityProgramming expressions
Algebraic Expressions Questions
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(x+y)^2=x2+xy^2+y^2
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(x+y)2=x^2+xy2+xy^2
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(x+y)^2=x^2+xy2+y^2
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(x+y)^2=xy2+xy2+y^2
C
Correct answer
Explanation
Option C matches the given expression (x+y)^2=x^2+xy2+y^2. The notation xy2 appears to represent the middle term 2xy in the binomial expansion. The standard form of (x+y)^2 is x^2 + 2xy + y^2, but this question uses compressed notation where xy2 serves as the middle term.
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x is greater than y
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y is greater than x
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More information is needed to descover the relationship between the two values
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x = y
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2x = y
D
Correct answer
Explanation
Simplify the left side: 3x + x = 4x. So 4x = 2x + 2y. Subtract 2x from both sides: 2x = 2y. Divide by 2: x = y. Option D is correct.
B
Correct answer
Explanation
Given 2X - Y = 4, we need 6X - 3Y. Factor out 3: 3(2X - Y) = 3 × 4 = 12. This tests recognition of common factors. Option A (15) would come from incorrectly distributing, option C (18) from multiplying only one term, option D (10) from random calculation.
A
Correct answer
Explanation
Given X = Y = 2Z, so Y = 2Z and X = 2Z as well. Then XYZ = (2Z)(2Z)(Z) = 4Z³ = 256, so Z³ = 64 and Z = 4. Therefore X = 2Z = 8. Option B (3), C (5), and D (6) don't satisfy the equation when substituted back.
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01jun2012
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21jul2012
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19175 - Numeric equivalent of the date 01jul2012
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21oct2012
C
Correct answer
Explanation
The SAS intnx function advances dates by intervals. intnx('year', '21oct2009'd, 3, 'mid') adds 3 years using 'mid' alignment, landing on July 1, 2012, which has SAS date value 19175.
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x=5, y=5
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x=5, y=6
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x=6, y=6
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x=6, y=5
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x=5, y=7
C
Correct answer
Explanation
This is the correct answer. Here student uses Pre increment operator of C programming language and increases the value of x by 1. After that he assigns the value of x to y and he also assigns new value to x, which is 6. So, both x and y contain 6.
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d - s - 70
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d - s + 70
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d + s - 70
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d - s
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d - 70
B
Correct answer
Explanation
The first bit of information is in fact irrelevant. What the second bit says is that from an account which had d dollars, she withdrew (s - 70) dollars. So, what will be left behind is d - (s - 70) = d - s + 70 dollars.
D
Correct answer
Explanation
This demonstrates the distributive property in Boolean algebra: x AND (y OR z) = (x AND y) OR (x AND z). The operation distributes over OR just like in regular algebra.
D
Correct answer
Explanation
-32y + 4 = -22y + 84
Bring subject terms on one side and non subject terms on other side.
-32y + 22y = 84 - 4
-10y = 80
Dividing both sides by -10
y= -8
D
Correct answer
Explanation
(123)_5 = 1×25 + 2×5 + 3 = 38 in decimal. For (x3)_y = 38, we need x×y + 3 = 38, so x×y = 35. Factor pairs of 35 with x < y (required for valid digit in base y) are (1,35) and (5,7), giving x = 1 or 5. The base y must exceed the highest digit (3), so y = 35 or 7 are both valid.
C
Correct answer
Explanation
x = (6X8)/4 = 12
Now, 2y + 12 = 7
Or y = - 5/2
D
Correct answer
Explanation
z = 1, k + s = 2, 3(y + 1) = 2y X 2, 3y + 3 = 4y, y = 3
D
Correct answer
Explanation
3{(x.y + y.z + x.z)} + 1 = 3{(1) (2) + (2) (0) + (1) (0)} + 1 = 3 X 2 + 1 = 6 + 1 = 7