Algebra Questions

Multiple choice
  1. there is only one root

  2. there are only two distinct roots

  3. there are only three distinct roots

  4. there are four distinct roots

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let y = |x|. The equation becomes y^2 - 5y + 6 = 0, which factors to (y - 2)(y - 3) = 0. Thus, |x| = 2 or |x| = 3. This gives x = 2, -2, 3, -3, resulting in four distinct roots.

Multiple choice
  1. real and distinct

  2. imaginary

  3. real and equal

  4. irrational

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Roots 2, 2 for x^2+px+b=0 implies sum = -p = 4 (p=-4), product = b = 4. Roots 1, 4 for x^2+ax+q=0 implies sum = -a = 5 (a=-5), product = q = 4. The equation x^2+ax+b=0 becomes x^2 - 5x + 4 = 0. Roots are (x-1)(x-4)=0, so roots are 1 and 4. These are real and distinct.

Multiple choice
  1. True

  2. False

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Roots > 3. Let f(x) = x^2 - 6ax + 9a^2 - 2a + 2 = 0. (x-3a)^2 = 2a - 2. x = 3a +/- sqrt(2a-2). Roots are 3a + sqrt(2a-2) and 3a - sqrt(2a-2). Both > 3: 3a - sqrt(2a-2) > 3 => 3a - 3 > sqrt(2a-2). Square both sides: 9(a-1)^2 > 2a-2. 9(a-1)^2 - 2(a-1) > 0. (a-1)(9a-9-2) > 0 => (a-1)(9a-11) > 0. So a > 11/9 or a < 1. The statement a < 11/9 is false.