Algebra Questions

Multiple choice
  1. Rational

  2. Irrational

  3. Real

  4. Imaginary

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

For ax^2 + x + b = 0, real roots imply discriminant D = 1 - 4ab > 0, so 4ab < 1. For the second equation x^2 - 4*sqrt(ab)x + 1 = 0, the discriminant is D' = (4*sqrt(ab))^2 - 4(1)(1) = 16ab - 4. Since 4ab < 1, then 16ab < 4, which means 16ab - 4 < 0. A negative discriminant indicates imaginary roots.

Multiple choice
  1. $p + q$
  2. $p - q$
  3. $\displaystyle \frac { p+q }{ 2 } $
  4. $ \displaystyle \frac { p-q }{ 2 } $
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

If the roots are x and -x, the equation 1/(x+p) + 1/(x+q) = 1/r becomes (2x + p + q) / (x^2 + x(p+q) + pq) = 1/r. Cross-multiplying gives r(2x + p + q) = x^2 + x(p+q) + pq. For the roots to be symmetric around zero, the coefficient of the x term must be zero, implying 2r = p + q, or r = (p+q)/2.