Mathematics · Quantitative Aptitude
Algebra and Arithmetic
406 Questions
Algebra and arithmetic questions cover fundamental mathematical operations, inequalities, and binomial products. They assess core quantitative reasoning skills required for various aptitude tests. Solving these problems strengthens the understanding of number systems and algebraic identities.
Binomial productsLinear inequalitiesLeast common multipleQuadratic equationsInteger properties
Algebra and Arithmetic Questions
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>0 for positive value
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0 for positive value
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0 for negative value
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1 for positive value
D
Correct answer
Explanation
The SIGN function returns: 1 for positive numbers, 0 for zero, and -1 for negative numbers. Option D correctly states it returns 1 for positive values. Options A and C are wrong because positive values return 1, not >0 or 0.
D
Correct answer
Explanation
The phrase “not negative” means any number that is zero or greater. The condition “>=0” includes zero and all positive numbers, satisfying the definition. In contrast, “=0” only covers zero, “>=1” omits zero, and “<=0” incorrectly includes negative values, so they are not correct.
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2^(n-1) to 2^(n+1)+1
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-2^(n-1) to 2^(n-1)-1
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-2^(n-1) to 2^(n-1)+1
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-2^(n-1) to 2^(n+1)-1
B
Correct answer
Explanation
For n-bit signed integers, the range is -2^(n-1) to 2^(n-1)-1. The negative side can go to -2^(n-1) (using the sign bit), while the positive side maxes at 2^(n-1)-1 since zero uses one positive value. This matches option B.
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a=a+2;
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a=a+3;
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a=a+1;
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a=a+4;
C
Correct answer
Explanation
The postfix increment operator a++ adds 1 to a and returns the original value (before increment). It is equivalent to a = a + 1. The increment happens after the value is used in the expression.
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Equal to 0
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Greater than or equal to 1
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Less than or equal to 0
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Greater than or equal to 0
D
Correct answer
Explanation
Not negative means a value is greater than or equal to zero (>=0). This includes zero and all positive numbers. It doesn't mean equal to 0 only, or >=1 (which excludes zero), or <=0 (which would include negative numbers).
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Equal to 0
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Greater than or equal to 1
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Less than or equal to 0
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Greater than or equal to 0
D
Correct answer
Explanation
Not negative means the value is either zero or positive. In mathematical notation, this is x >= 0. A value greater than or equal to 1 would exclude zero, while less than or equal to 0 would only include negative numbers and zero.
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Equal to 0
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Greater than or equal to 1
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Less than or equal to 0
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Greater than or equal to 0
D
Correct answer
Explanation
A number that is 'not negative' cannot be less than 0. The number 0 itself is not negative, and all positive numbers are also not negative. Therefore, 'not negative' means the number is greater than or equal to 0 (x ≥ 0).
A,B,C
Correct answer
Explanation
SQL and databases use multiple operators to express inequality: != is the most common, ^= is used in some SQL dialects (including Oracle), and <> is the SQL-92 standard operator. The !== operator is not a standard SQL comparison operator.
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G(x) contains more than two terms
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G(x) does not divide 1 + xk, for any k not exceeding the frame length
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1 + x is a factor of G(x)
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G(x) has an odd number of terms.
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$R=0$
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$R<0$
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$R \geq 0$
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$R > 0$
C
Correct answer
Explanation
R = E[X²] - (E[X])² is the definition of variance, which is always non-negative because variance measures spread and cannot be negative. R = 0 only when the random variable is constant. R > 0 when the variable has any variation. Therefore R >= 0 is always true.
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G(x) contains more than two terms
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G(x) does not divide 1 + xk, for any k not exceeding the frame length
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1 + x is a factor of G(x)
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G(x) has an odd number of terms.
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$\bar AC + B\bar C + AC$
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$\bar BC + AC + B\bar C+\bar A C \bar B$
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$AC+B\bar C + \bar B C + ABC$
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$ABC + \bar A B \bar C + AB \bar C + A \bar B C$
D
Correct answer
Explanation
$$
\begin{array}
AC + B\bar C &= AC_1 + B \bar C_1 \\
&= AC(B+\bar B) + B\bar C(A+\bar A) \\
&= ACB + AC\bar B + B\bar C A + B\overline{CA}
\end{array}
$$
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X = $A\bar B \bar C+ \bar A B \bar C + \bar A \bar B C + ABC$
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X = $\bar A BC + A\bar B C + AB\bar C + \bar A \bar B \bar C$
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X = $AB + BC+ AC$
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X = $\bar A \bar B + \bar B \bar C + \bar B \bar C + \bar A \bar C$
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((∀x)[α] ⇒ (∀x)[β]) ⇒ (∀x)[α ⇒ β]
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(∀x)[α] ⇒ (∃x)[α ∧ β]
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((∀x)[α ∨ β] ⇒ (∃x)[α]) ⇒ (∀x)[α]
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(∀x)[α ⇒ β] ⇒ ((∀x)[α]) ⇒ (∀x)[β])
D
Correct answer
Explanation
We know that,
If the four tense operators, P, F, H and G and following axions are
$G (Q\rightarrow R)\rightarrow (GQ \rightarrow GR)$
$H (Q\rightarrow R) \rightarrow (HQ\rightarrow HR)$
$G - HQ \rightarrow Q$
$- H - GQ\rightarrow Q$
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$ ++\*+ABC\*DE\*FG $
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$ +\*++ABC\*DE\*FG $
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$AB+C\*DE\*+FG\*+$
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$ABC+\*DE\*+FD\*+$
A
Correct answer
Explanation
$(+AB)*C+(*DE)+(*FG)$
$= *+ABC+(*DE)+(*FG)$
$=+ + * + ABC * DE * FG$