Mathematics · Quantitative Aptitude

Algebra and Arithmetic

406 Questions

Algebra and arithmetic questions cover fundamental mathematical operations, inequalities, and binomial products. They assess core quantitative reasoning skills required for various aptitude tests. Solving these problems strengthens the understanding of number systems and algebraic identities.

Binomial productsLinear inequalitiesLeast common multipleQuadratic equationsInteger properties

Algebra and Arithmetic Questions

Multiple choice technology databases
  1. >0 for positive value

  2. 0 for positive value

  3. 0 for negative value

  4. 1 for positive value

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The SIGN function returns: 1 for positive numbers, 0 for zero, and -1 for negative numbers. Option D correctly states it returns 1 for positive values. Options A and C are wrong because positive values return 1, not >0 or 0.

Multiple choice technology mainframe
  1. = 0

  2. >=1

  3. <=0

  4. >=0

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The phrase “not negative” means any number that is zero or greater. The condition “>=0” includes zero and all positive numbers, satisfying the definition. In contrast, “=0” only covers zero, “>=1” omits zero, and “<=0” incorrectly includes negative values, so they are not correct.

Multiple choice technology programming languages
  1. 2^(n-1) to 2^(n+1)+1

  2. -2^(n-1) to 2^(n-1)-1

  3. -2^(n-1) to 2^(n-1)+1

  4. -2^(n-1) to 2^(n+1)-1

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For n-bit signed integers, the range is -2^(n-1) to 2^(n-1)-1. The negative side can go to -2^(n-1) (using the sign bit), while the positive side maxes at 2^(n-1)-1 since zero uses one positive value. This matches option B.

Multiple choice technology mainframe
  1. Equal to 0

  2. Greater than or equal to 1

  3. Less than or equal to 0

  4. Greater than or equal to 0

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Not negative means a value is greater than or equal to zero (>=0). This includes zero and all positive numbers. It doesn't mean equal to 0 only, or >=1 (which excludes zero), or <=0 (which would include negative numbers).

Multiple choice technology mainframe
  1. Equal to 0

  2. Greater than or equal to 1

  3. Less than or equal to 0

  4. Greater than or equal to 0

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Not negative means the value is either zero or positive. In mathematical notation, this is x >= 0. A value greater than or equal to 1 would exclude zero, while less than or equal to 0 would only include negative numbers and zero.

Multiple choice technology programming languages
  1. Equal to 0

  2. Greater than or equal to 1

  3. Less than or equal to 0

  4. Greater than or equal to 0

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

A number that is 'not negative' cannot be less than 0. The number 0 itself is not negative, and all positive numbers are also not negative. Therefore, 'not negative' means the number is greater than or equal to 0 (x ≥ 0).

Multiple choice
  1. $R=0$
  2. $R<0$
  3. $R \geq 0$
  4. $R > 0$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

R = E[X²] - (E[X])² is the definition of variance, which is always non-negative because variance measures spread and cannot be negative. R = 0 only when the random variable is constant. R > 0 when the variable has any variation. Therefore R >= 0 is always true.

Multiple choice
  1. $\bar AC + B\bar C + AC$
  2. $\bar BC + AC + B\bar C+\bar A C \bar B$
  3. $AC+B\bar C + \bar B C + ABC$
  4. $ABC + \bar A B \bar C + AB \bar C + A \bar B C$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

$$ \begin{array} AC + B\bar C &= AC_1 + B \bar C_1 \\ &= AC(B+\bar B) + B\bar C(A+\bar A) \\ &= ACB + AC\bar B + B\bar C A + B\overline{CA} \end{array} $$

Multiple choice
  1. X = $A\bar B \bar C+ \bar A B \bar C + \bar A \bar B C + ABC$
  2. X = $\bar A BC + A\bar B C + AB\bar C + \bar A \bar B \bar C$
  3. X = $AB + BC+ AC$
  4. X = $\bar A \bar B + \bar B \bar C + \bar B \bar C + \bar A \bar C$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Multiple choice
  1. ((∀x)[α] ⇒ (∀x)[β]) ⇒ (∀x)[α ⇒ β]

  2. (∀x)[α] ⇒ (∃x)[α ∧ β]

  3. ((∀x)[α ∨ β] ⇒ (∃x)[α]) ⇒ (∀x)[α]

  4. (∀x)[α ⇒ β] ⇒ ((∀x)[α]) ⇒ (∀x)[β])

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

We know that, If the four tense operators, P, F, H and G and following axions are $G (Q\rightarrow R)\rightarrow (GQ \rightarrow GR)$ $H (Q\rightarrow R) \rightarrow (HQ\rightarrow HR)$ $G - HQ \rightarrow Q$ $- H - GQ\rightarrow Q$