Mathematics · Quantitative Aptitude

Algebra and Arithmetic

406 Questions

Algebra and arithmetic questions cover fundamental mathematical operations, inequalities, and binomial products. They assess core quantitative reasoning skills required for various aptitude tests. Solving these problems strengthens the understanding of number systems and algebraic identities.

Binomial productsLinear inequalitiesLeast common multipleQuadratic equationsInteger properties

Algebra and Arithmetic Questions

Multiple choice
  1. Positive integer

  2. A negative integer

  3. Either a positive integer or a negative integer

  4. None of these

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The product of two negative integers is always a positive integer (e.g., -2 * -3 = 6).

Multiple choice
  1. (-8) + (-4) > (-8) - (-4)

  2. (-8) + (-4) < (-8) - (-4)

  3. (-8) + (-4) = (-8) - (-4)

  4. None of these

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Calculating both sides: (-8) + (-4) = -12, while (-8) - (-4) = -8 + 4 = -4. Since -12 is less than -4, the statement (-8) + (-4) < (-8) - (-4) is true.

Multiple choice
  1. A = 7 , B = 9

  2. A = 0 , B = 1

  3. A = 1 , B = 0

  4. A = 9 , B = 7

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

(10A + 1) + (10 + B) = 10B + 0. Simplifying: 10A + B + 11 = 10B. 10A + 11 = 9B. Testing A=7: 70 + 11 = 81, so 9B = 81, B = 9. This matches.

Multiple choice
  1. ( x + 2 ) 2 = x2+4

  2. ( a2+b2)=( a + b )2

  3. 2/3x +2 = 2/3x +2

  4. None of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Option C is an identity (2/3x + 2 = 2/3x + 2). Option A is incorrect because (x+2)^2 = x^2 + 4x + 4. Option B is incorrect because a^2 + b^2 is not (a+b)^2.

Multiple choice
  1. 2a2b2

  2. 2a2 + b2

  3. 2( a2+b2)

  4. 4ab

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Expand both squares: (a^2 + 2ab + b^2) + (a^2 - 2ab + b^2). The 2ab and -2ab cancel out, leaving 2a^2 + 2b^2, which is 2(a^2 + b^2).

Multiple choice comparison of irrational numbers surds and law of surds rational and irrational numbers exponents maths

$if\,A\, = \sqrt 7  - \sqrt 6 \,and\,B = \,\sqrt 6  - \sqrt {5,} \,then\,$

  1. $A > B$
  2. $A = B$
  3. $A < B\,$
  4. $A \geqslant B$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
Given numbers are $A=\sqrt{7}-\sqrt{6}$ and $B=\sqrt{6}- \sqrt{5}$
Let $x =\sqrt{5}$ and $y= \sqrt{7}$ then by
$A.M$ and $G.M$
$\dfrac{x+y}{2} \le \sqrt{\dfrac{x^{2}+y^{2}}{2}}$
$\Rightarrow \dfrac{\sqrt{5}+ \sqrt{7}}{2} \le \sqrt{6}$
$\Rightarrow \sqrt{5}+ \sqrt{7} \le 2 \sqrt{6}$
$\Rightarrow \sqrt{7}- \sqrt{6} \le \sqrt{6} - \sqrt{5}$