Quantitative Aptitude
Problems on Ages
1,744 Questions
Problems on Ages Questions
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$5\ years$
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$7\ years$
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$4\ years$
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$6\ years$
C
Correct answer
Explanation
Let age be x. x + 12 = x^2. x^2 - x - 12 = 0. (x - 4)(x + 3) = 0. Since age must be positive, x = 4.
D
Correct answer
Explanation
Let F and S be current ages. (F-18) = 3(S-18) and F = 2S. Substituting F=2S into the first gives 2S-18 = 3S-54, so S=36 and F=72. Sum = 36+72 = 108.
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$\text{sarla age}=31,$ $\text{shreya age}=12$
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$\text{sarla age}=12,$ $\text{shreya age}=34$
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$\text{sarla age}=12,$ $\text{shreya age}=31$
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$\text{sarla age}=15,$ $\text{shreya age}=34$
C
Correct answer
Explanation
S = 2K + 7. (S+3) = (K+3) + 19 => S = K + 19. 2K + 7 = K + 19 => K = 12. S = 12 + 19 = 31.
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$10, 30$
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$20, 60$
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$30, 90$
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$15, 45$
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$20$ years
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$25$ years
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$10$ years
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$15$ years
A
Correct answer
Explanation
Let sister's age be S and Sumit's be U. 5 years ago: U-5 = 3(S-5). Present: U = 2S. Substitute: 2S-5 = 3S-15. S = 10. Sumit = 2 * 10 = 20.
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$14$ yrs.
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$16$ yrs.
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$11$ yrs.
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$13$ yrs.
A
Correct answer
Explanation
Shyam's 8th birthday was 3 years ago, so he is 8 + 3 = 11. In 10 years, Shyam will be 21. Father's age in 10 years = 2(21) + 12 = 54. Father's current age = 54 - 10 = 44. Ram's age = 1/3 * 44 = 14.66. The answer 14 is the closest integer.
A
Correct answer
Explanation
Sum of ages 3 years ago = 59. Current sum = 59 + 3 + 3 = 65. Sum 5 years ago = 65 - 5 - 5 = 55.
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$23\ years$
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$40\ years$
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$27\ years$
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$44\ years$
C
Correct answer
Explanation
Let A and B be current ages. (A-10)/(B-10) = 13/17 => 17A - 170 = 13B - 130 => 17A - 13B = 40. (A+17)/(B+17) = 10/11 => 11A + 187 = 10B + 170 => 10B - 11A = 17. Solving this system gives B = 27.
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Present age of father is $60$ years and present age of son is $20$ years
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Present age of father is $35$ years and present age of son is $15$ years
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Present age of father is $65$ years and present age of son is $25$ years
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Present age of father is $50$ years and present age of son is $15$ years
B
Correct answer
Explanation
Let F and S be current ages. (F-5) = 3(S-5) => F = 3S - 10. (F+5) = 2(S+5) => F = 2S + 5. Equating: 3S - 10 = 2S + 5 => S = 15. Then F = 2(15) + 5 = 35.
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$55$ years, $24$ years
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$34$ years, $12$ years
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$48$ years, $19$ years
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$42$ years, $18$ years
B
Correct answer
Explanation
Let F, S be present ages. (F-10) = 12(S-10) => F-10 = 12S - 120 => F = 12S - 110. (F+10) = 2(S+10) => F+10 = 2S + 20 => F = 2S + 10. 12S - 110 = 2S + 10 => 10S = 120 => S = 12. F = 2(12) + 10 = 34.
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Present age of $A = 29$ years and that of $B = 11$ years
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Present age of $A = 25$ years and that of $B = 10$ years
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Present age of $A = 65$ years and that of $B = 20$ years
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Present age of $A = 40$ years and that of $B = 10$ years
B
Correct answer
Explanation
Let A and B be current ages. (A-5) = 4(B-5) => A - 4B = -15. (A+5) = 2(B+5) => A - 2B = 5. Subtracting equations: 2B = 20, so B = 10. Then A = 25.
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Diana $21$ years, Jim $16$ years
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Diana $15$ years, Jim $14$ years
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Diana $15$ years, Jim $16$ years
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Diana $20$ years, Jim $14$ years
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$45, 15$
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$30, 40$
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$50, 30$
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$50 , 20$
D
Correct answer
Explanation
Let A and B be current ages. (A-5) = 3(B-5) => A = 3B - 10. (A+10) = 2(B+10) => A = 2B + 10. Equating: 3B - 10 = 2B + 10 => B = 20. Then A = 50.
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$10 + 5x = 7$
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$5x -10 = 7$
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$10 \times 5x = 7$
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$10 = 5x - 7$
B
Correct answer
Explanation
Let John's age be x. Sister's age = 5x - 10. Given sister's age is 7, so 5x - 10 = 7.
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$2 + 2x = 45$
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$4 - 2x = 45$
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$4 + 2x + 45$
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$4 + 2x = 45$
D
Correct answer
Explanation
Let Judah's age be x. Mother's age = 2x + 4. Given mother's age is 45, the equation is 2x + 4 = 45.