Quantitative Aptitude

Problems on Ages

1,744 Questions
All Translate multiples, fractions, and percentages 518 Use two ratios from different dates 500 Convert an age ratio into actual ages 258 Handle averages and changing groups 167 Generational age chains 111 Recognize equal age gaps 101 Product of ages 68 Ages in arithmetic progression 11 Division of lifespan 9

Problems on Ages Questions

Multiple choice

Sum of the present ages of A, B, C and D is 88 years. After 8 years ratio of their ages is 5 : 6 : 9 : 10 . What is C’s present age?

  1. 28 years

  2. 36 years

  3. 32 years

  4. 30 years

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let present ages be a, b, c, d. Sum: a + b + c + d = 88. After 8 years: (a+8):(b+8):(c+8):(d+8) = 5:6:9:10. Total parts = 30. Each part = (88 + 4×8)/30 = 120/30 = 4. C's age after 8 years = 9×4 = 36. Present age = 36 - 8 = 28 years.

Multiple choice

The average age of Yogita, Kanika and Prachi is 14 years. The ratio of Yogita‘s age one year ago to Kanika‘s age one years hence to Prachi‘s age three years hence is 5 : 6 : 4. Find ratio of Yogita’s age two years hence to Prachi’s age.

  1. 8: 5

  2. 5: 3

  3. 1: 4

  4. 2: 1

  5. 4: 7
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let current ages be Y, K, P. Average = 14, so Y + K + P = 42. Given ratio (Y-1) : (K+1) : (P+3) = 5 : 6 : 4. Let Y-1 = 5x, K+1 = 6x, P+3 = 4x. Then Y = 5x+1, K = 6x-1, P = 4x-3. Substituting: (5x+1) + (6x-1) + (4x-3) = 42, so 15x - 3 = 42, 15x = 45, x = 3. Ages: Y = 16, K = 17, P = 9. We need (Y+2) : P = 18 : 9 = 2 : 1. Option D is correct. The ratio calculation works out cleanly.

Multiple choice

The A’s present ages is 2.6 times of B’s present age . After 8.5 years, A’s age will be 1.8 times of B’s age . Then find present ages of A and B ?

  1. 22.1 years , 8.5 years

  2. 21.2 years, 18.5 years

  3. 12.1 years, 15.8 years

  4. 22.22 years, 8.8 years

  5. None of These
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let B's present age = b. Then A = 2.6b. After 8.5 years: A + 8.5 = 1.8(B + 8.5). Substituting: 2.6b + 8.5 = 1.8b + 15.3, giving 0.8b = 6.8, so b = 8.5. Then A = 2.6 × 8.5 = 22.1. Option A matches these values exactly.

Multiple choice

Ten years ago, the age of a man was 20 years less than 6 times his son's age. Ten years hence, his age will be 30 years less than thrice his son's age. After how many years from now will their combined age be 90 years?

  1. 5

  2. 10

  3. 15

  4. 20
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the man's current age be m and son's current age be s. From 10 years ago: m-10 = 6(s-10) - 20, giving m = 6s - 70. From 10 years hence: m+10 = 3(s+10) - 30, giving m = 3s - 10. Solving: 6s - 70 = 3s - 10, so 3s = 60 and s = 20. Then m = 50. Current combined age is 70. After x years: 70 + 2x = 90, so x = 10.

Multiple choice

Ten years ago, Manisha was half of Atul in age. If the ratio of their present ages is 3: 4, what will be the total of their present ages?

  1. 33 years

  2. 37 years

  3. 35 years

  4. 41 years
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let present ages be 3x and 4x (ratio 3:4). Ten years ago: (3x - 10) = 1/2 × (4x - 10). Solving: 3x - 10 = 2x - 5, giving x = 5. Present ages: Manisha = 15, Atul = 20. Total = 35 years. Check: 10 years ago they were 5 and 10, and indeed 5 = 1/2 × 10.

Multiple choice

If 6 years are subtracted from the present age of Ayush and takes 25% of that then we get the present age of his only son. 4 years ago, his daughter’s age is 7 years more than his son. Sum of daughter’s present age and his wife’s present age is 10 years more than Ayush’s present age then find the present age of Ayush if average of present age of entire family is 30.25 year?

  1. 45

  2. 50

  3. 60

  4. 40

  5. 36
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let Ayush's age = A. Son's age = 0.25(A-6). Daughter 4 years ago = son + 7, so D-4 = 0.25(A-6) + 7, D = 0.25A + 8.5. D + W = A + 10. Family: Ayush, wife, son, daughter. Sum ages = 4 * 30.25 = 121. A + (A+10-D) + 0.25(A-6) + D = 121. A + A + 10 - 0.25A - 8.5 + 0.25A - 1.5 + 0.25A + 8.5 = 121. 2A + 0.25A + 8.5 = 121.5A = 113, A ≈ 50. Answer B is correct.

Multiple choice

Samir's age is one – fourth of his father's age and two – third of his sister Reema's age. What is the ratio of the ages of Samir, Reema and their father respectively?
  1. $3: 2: 8$
  2. $3: 4: 8$
  3. $2: 3: 8$
  4. $4: 3: 8$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let Samir's age be 1 unit. Then his father's age is 4 units (since Samir is one-fourth). Samir is also two-thirds of Reema's age, so Reema's age is 3/2 units. Converting to whole numbers: Samir:Reema:Father = 2:3:8.

Multiple choice

A father's age is now three times that of his elder daughter. Five years back his age was eight times that of his younger daughter .If the difference of ages of the two daughters is 5 years ,what is the age of the father now?

  1. 50

  2. 60

  3. 45

  4. 55
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the father's age be F, elder daughter be E, and younger daughter be Y. From the problem: F = 3E, F-5 = 8(Y-5), and E-Y = 5. Substituting E = Y+5 into F = 3E gives F = 3(Y+5) = 3Y+15. Also from the second equation: F-5 = 8Y-40, so F = 8Y-35. Equating both expressions: 3Y+15 = 8Y-35, giving 5Y = 50, so Y = 10. Then E = 15 and F = 45. The father is currently 45 years old.

Multiple choice

Arjit's age is 3 years more than 1.5 times the age of Heera, whose age is 10 years more than (\frac{2}{3}) the age of Deepika. If 5 times the age of Deepika is equal to 3 times the age of Arjit, what is the sum of the present ages of all three?

  1. 99 years

  2. 95 years

  3. 100 years

  4. 97 years
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let D = Deepika's age. Heera = (2/3)D + 10. Arjit = 1.5 × Heera + 3 = 1.5((2/3)D + 10) + 3 = D + 15 + 3 = D + 18. Given: 5D = 3 × Arjit = 3(D + 18) = 3D + 54. So 5D = 3D + 54, meaning 2D = 54, thus D = 27. Heera = (2/3)(27) + 10 = 18 + 10 = 28. Arjit = 27 + 18 = 45. Sum = 27 + 28 + 45 = 100 years.

Multiple choice

Anushika’s father was 27 years of age when she was born while her mother was 23 years old when her brother 2 years elder than her was born. What is the difference between the ages of her parents?

  1. 1 years

  2. 2 years

  3. 3 years

  4. 4 years

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

When Anushika was born, her father was 27. When her brother (2 years older than her) was born, her mother was 23, so when Anushika was born, her mother was 23 + 2 = 25. Age difference = 27 - 25 = 2 years.

Multiple choice

5 years ago, the ratio of A’s and B’s age is 5 : 4 . The sum of the present ages of A , B and C is 110 years . If C’s present age is equal to the sum of present ages of A and B . What is the present age of A ?

  1. 30 years

  2. 25 years

  3. 35 years

  4. 55 years

  5. None of These
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

5 years ago: A=5x, B=4x. Present: A=5x+5, B=4x+5. Given C=A+B and A+B+C=110. So 2(A+B)=110, A+B=55. Then 9x+10=55, x=5. Present age of A = 5(5)+5 = 30 years.

Multiple choice

The sum of the present ages of two persons is seven times that of the difference between their ages. After 5 years, the sum of their ages will become nine times that of the difference. What is the present age of the elder person?

  1. 24 years

  2. 28 years

  3. 14 years

  4. 20 years
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let ages be x (elder) and y. Given: x+y=7(x-y) and (x+5)+(y+5)=9(x-y). Simplify first: x+y=7x-7y → 8y=6x → x=4y/3. Second: x+y+10=9x-9y → 10y+10=8x → substitute x: 10y+10=8(4y/3) → 30y+30=32y → y=15, x=20. Elder is 20.

Multiple choice

The ratio between the present ages of Rohit and Rina is 1:3. Find the present age of Rina. Statement I: Difference between the present ages of Pooja and Rohit is 11 years. Statement II: The present age of Pooja is 2 years less than thrice the present age of Rohit. Statement III: Difference between the present ages of Rina and Rohit is 13 years.

  1. Only III

  2. Either I and II together or III alone

  3. All are together

  4. Only I and II

  5. None of the statements
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Given Rohit:Rina = 1:3, let Rohit = x, Rina = 3x. Method 1 (III alone): Difference Rina - Rohit = 13, so 3x - x = 13, 2x = 13, x = 6.5. Rina = 19.5 years. Method 2 (I and II): Pooja - Rohit = 11, and Pooja = 3×Rohit - 2. So 3x - 2 - x = 11, 2x = 13, x = 6.5. Rina = 19.5 years. Either method gives same answer. Option B is correct.

Multiple choice

The present age of Sakshi is 7/5 times of her age at the time of her marriage and her son is 1/7 of her age. Sakshi married 8 years ago. Find the ratio of Sakshi age to her son’s age after 12 years ?

  1. 4 : 3

  2. 5 : 2

  3. 6 : 5

  4. 7 : 5

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let Sakshi's marriage age = M. Current age = 7M/5. She married 8 years ago, so 7M/5 - M = 8, giving 2M/5 = 8, M = 20. Current age = 7 × 20/5 = 28. Son is 1/7 of her age = 28/7 = 4 years. After 12 years: Sakshi = 28 + 12 = 40, Son = 4 + 12 = 16. Ratio = 40:16 = 5:2. The ratio is 5:2.