Acoustics and Sound Waves

The string of a violin emits a note of 205 Hz at its correct tension. The string is tightened slightly and then it produces six beats in two seconds with a tuning fork of frequency 205 Hz. The frequency of the note emitted by the taut string is

A stretched string resonates with tuning fork frequency $512\ Hz$ When of the string is $0.5\ $. The length of the string required to vibrate resonantly with a tuning fork of frequency $256\ Hz$ would  be

If $n,2n,3n$ are the fundamental frequencies of the three segments into which a string is divided by placing required number of bridges below it. If $n _0$ is the fundamental frequency of the string, then 

Two tuning forks when sounded together produce 5 beat per second. The first tuning fork is in resonance with 16.0 cm wire of a sonometer and the second is in resonace with 16.2 cm wire of the same sonometer. The frequencies of the tuning forks are

A sonometre wire resonates with a given tuning forck forming standing waves with five antinodes between the two bridges when a mass of $9kg$is suspended from the wire. When this mass is replaced by mass $M$, the wire resonates with the same positions of the bridges. Then find the value of square roof of $M$.

String $B$ has twice the length, twice the diameter, twice the tension and twice the density of string $A$. The overtone of $B$ that will be in unison with fundamental frequency of $A$ is 

An open tube is in resonance with string (frequency of vibration of tube in $n _{0}$. If tube is dipped on water is that 75% of length of tube is inside water, then the ratio of the frequency of tube to string now will be 

1 meter long stretched wire of a sonometer vibrates with its fundamental frequency of 256 Hz. If the length of the wire is decreased to 25 cm and the tension remains the same, then the fundamental frequency of vibration will be:-