Physics · Science General
Acoustics and Sound Waves
2,006 Questions
Acoustics and sound waves deal with mechanical vibrations traveling through media like air and water. Key concepts include wave reflection, beats, echoes, the Mach number, and infrasound. These physics fundamentals are regularly tested in general science sections of multiple competitive exams.
Sound wave propagationEchoes and reflectionWave interferenceMach numberInfrasound frequency
Acoustics and Sound Waves Questions
Name the characteristic of the sound affected due to a change in its amplitude.
-
Loudness.
-
Wavelength.
-
Frequency.
-
Waveform.
A
Correct answer
Explanation
Amplitude is the size of the vibration, and this determines how loud the sound is. Larger vibrations make a louder sound.
The intensity or loudness of a sound depends upon the extent to which the sounding body vibrates, i.e., the amplitude of vibration. A sound is louder as the amplitude of vibration is greater, and the intensity decreases as the distance from the source increases.
Hence, loudness of the sound is affected due to the change in its amplitude.
As we move away from the source along with the amplitude which of the following quantity decreases as well ?
-
waveform
-
loudness
-
wavelength
-
intensity
B
Correct answer
Explanation
The intensity or loudness of a sound depends upon the extent to which the sounding body vibrates, i.e., the amplitude of vibration. A sound is louder as the amplitude of vibration is greater, and the intensity decreases as the distance from the source increases. Loudness is measured in units called decibels.
Loudness depends on the square of the amplitude of the wave. That is, $loudness{ \propto \left( amplitude \right) }^{ 2 }$.
Hence, As it moves away from the source its amplitude as well as its loudness decreases.
By reducing the amplitude of a sound wave, its :
-
Pitch increases
-
Loudness decreases
-
Loudness increases
-
Pitch decreases
B
Correct answer
Explanation
The loudness of sound is directly proportional to amplitude of sound wave.
loudness $\propto$ amplitude
Hence on reducing amplitude the loudness also decreases.
Unit for measuring the loudness of sound is _________________.
-
Decibel
-
Pascal
-
Newton
-
Newton-metre
A
Correct answer
Explanation
Unit for measuring the loudness of sound is decibel.
The intensity or loudness of a sound depends upon the extent to which the sounding body vibrates, i.e., the amplitude of vibration. A sound is louder as the amplitude of vibration is greater, and the intensity decreases as the distance from the source increases. Loudness is measured in units called decibels.
Sound levels are measured in
-
Decimeters
-
Decibels
-
Deciliters
-
Decigrams
B
Correct answer
Explanation
Answer is B.
The intensity or loudness of a sound depends upon the extent to which the sounding body vibrates, i.e., the amplitude of vibration. A sound is louder as the amplitude of vibration is greater, and the intensity decreases as the distance from the source increases.
Sound levels is measured in units called decibels.
If the amplitude of the sound is made 3 times its initial value, then its loudness will become _______________ times its initial value.
A
Correct answer
Explanation
If the amplitude of the sound is made 3 times its initial value, then its loudness will become nine times its initial value.
Loudness depends on the square of the amplitude of the wave.
That is, $Loudness\propto { (Amplitude) }^{ 2 }$.
Thus, when amplitude of the wave is tripled, the loudness increases nine times.
The loudness of sound is measured in _______ .
-
decibels
-
metres
-
kilograms
-
seconds
A
Correct answer
Explanation
The loudness of sound is measured in units called decibels (dB). A decibel unit expresses the relative intensity of sounds on a scale from zero for the average least perceptible sound to about 100 dB, which is near the level most people find uncomfortably loud.
Identify the scale which can be used to measure the intensity of sound?
-
decibel
-
acoustic
-
ultrasound
-
infrasound
-
Hertz
A
Correct answer
Explanation
Intensity (or loudness) of sound $L =10 \log _{10} \dfrac{I}{I _o}$
It is measured in decibel (dB)
A normal human being can hear sound having an intensity level of maximum ...................
-
50 dB
-
80 dB
-
100 dB
-
150 dB
B
Correct answer
Explanation
Decibel levels help us to understand the loudness of a sound with respect to a reference level. A decibel level of zero dB represents the lowest level of sound and a level of 80 dB represents the level of pain for humans.
How many order of magnitude more powerful is 90 dB sound than 40 dB sound?
D
Correct answer
Explanation
$90 = 10 log (\dfrac{I _{1}}{I})$
$40 = 10 log (\dfrac{I _{2}}{I})$
$90 - 40 = 10 log (\dfrac{I _{1}}{I _{2}})$
$\dfrac{I _{1}}{I _{2}} = 10^{5}$
If the intensity of sound is increased by a factor of 30 , by how many decibels is the sound level increased ?
-
12 dB
-
14.77 dB
-
10 dB
-
13 dB
B
Correct answer
Explanation
The intensity of sound in increased by factor $30$
Let $2$ be the intensity of previous sound
Intensity of recent sound $I=30I$
$\beta =10 \log\dfrac{I}{I _o}$
$\beta _1=10 \log\dfrac{I}{I _o}$ where intensity of sound is $ I$
$\beta _1=10 \log\dfrac{30I}{I _o}$ when intensity of sound is $I$
Increased in sound level $\Rightarrow \beta _2-\beta _1$
$=10 \log\dfrac{30I}{I _o}-10\log \dfrac{I}{I _o}$
$=10 \log 30$
$10 \log \dfrac{30 I}{I}$
$=14.77d\beta$.
When a person wears a hearing aid, the sound intensity level increases by 30 dB. The sound intensity increases by
-
e$^{3}$
-
10$^{3}$
-
30
-
10$^{2}$
B
Correct answer
Explanation
Let the intensity of the sound without hearing Aid is $I _0$, and the
intensity after wearing hearing aid is $I$, then from the formula,
$L _{db}=10 \log _{10}{\dfrac{I}{I _0}}$
$30=10 \log _{10}{\dfrac{I}{I _0}}$
$\dfrac{I}{I _0}=10^3$
$I=10^3 \times I _0$
Option "B" is correct.
Spherical sound waves are emitted uniformly in all directions from a point source. The variation in sound level SL as a function of distance 'r' from the source can be written as
-
SL = -b log r$^{a}$
-
SL = a - b (log r)$^{2}$
-
SL = a - b log r
-
SL = a - b/r$^{2}$
C
Correct answer
Explanation
we know $SL = 10 log \dfrac{I}{I _o}$
$I = \dfrac{P}{4\pi r^2}$ where P is the power of the source
$SL = 10 log\dfrac{P}{4\pi r^2I _o} = 10 log \dfrac{P}{4\pi I _o} - 10 log r^2 = 10 log \dfrac{P}{4\pi I _o} - 20 log r = a - b log r$
The intensity level of two sounds are 100 dB and 50 dB. What is the ratio of their intensities?
-
10$^{1}$
-
10$^{3}$
-
10$^{5}$
-
10$^{10}$
C
Correct answer
Explanation
Loudness of two sounds is given as $L _2 = 100 \ dB$ and $L _1 = 50 \ dB$
Loudness of sound $L = 10 \log _{10}\dfrac{I}{I _o}$
$\implies$ $L _2 - L _1 = 10\log _{10}\dfrac{I _2}{I _1}$
Or $100 - 50 = 10\log _{10}\dfrac{I _2}{I _1}$
Or $\log _{10}\dfrac{I _2}{I _1} = 5$
Or $\dfrac{I _2}{I _1} = 10^5 $
A source of sound emits 200 W power which is uniformly distributed over a sphere of radius 10 m. What is the loudness of sound on the surface of sphere?
D
Correct answer
Explanation
Intensity is given by:
$I=\dfrac{W}{4\pi{r}^2}$
$I=\dfrac{200}{4\pi\times 100} =0.159W/m^2$
In terms of decibels, $I=10\log _{ 10 }{ I } +120 dB$
$I=112dB$