🎴 Flashcard Mode
2004|Electronics and Comm (GATE Exam)-Previous Question Paper Solution
Card1 / 89
Mastered0
Review0
QuestionClick to flip
The minimum number of 2- to -1 multiplexers required to realize a 4- to -1 multiplexers is
AnswerClick to flip back
A
3
💡 Explanation:
Number of MUX is $\dfrac{4}{3}$= 2 and $\dfrac{2}{2}$= 1
Thus, the total number 3 multiplexers is required.