Network Graphs and Circuit Analysis - ECE
A comprehensive test on network graphs, circuit analysis techniques, impedance calculations, and power transfer in Electronics and Communication Engineering.
Questions
In the interconnection of ideal sources shown in the figure, it is known that the 60 V source is absorbing power.

Which of the following can be the value of the current source I?
- 10 A
- 13 A
- 15 A
- 18 A
The RC circuit shown in the figure is

- a low-pass filter
- a high-pass filter
- a band-pass filter
- a band-reject filter
A series RLC circuit has a resonance frequency of 1 kHz and a quality factor Q = 100. If each R, L and C is doubled from its original value, the new Q of the circuit is
- 25
- 50
- 100
- 200
In the circuit shown below, the value of RL such that the power transferred to RL is maximum is
- 5$\Omega$
- 10$\Omega$
- 15$\Omega$
- 20$\Omega$
The ABCD parameters of an ideal n : 1 transformer shown in figure are $
\left[
\begin{array}
\ n & 0 \\
0 & x
\end{array}
\right]
$. The value of X will be

- n
- $\dfrac{1}{n}$
- n2
- $\dfrac{1}{n^2}$
A circuit consists of a resistor, an inductor and a capacitor connected in series to a 150 V AC mains. For the circuit, R = 9 Ohms, XL = 28 Ohms and XC = 16 Ohms. What is the value of the current in the circuit?
- 10 A
- 15 A
- <font size="2"><font face="Arial">20 A</font></font>
- 25 A
Impedance Z as shown in the figure is

- $j29\Omega$
- $j9\Omega$
- $j19\Omega$
- $j39\Omega$
For the circuit shown in the figure, the initial conditions are zero. Its transfer function H(s) =$\dfrac{V_0(s)}{V_i(s)}$is
- $\dfrac{1}{s^2 + 10^6s + 10^6}$
- $\dfrac{10^6}{s^2 + 10^3s + 10^6}$
- $\dfrac{10^3}{s^2 + 10^3s + 10^6}$
- $\dfrac{10^6}{s^2 + 10^6s + 10^6}$
With 10 V dc connected at port A in the linear nonreciprocal two-port network shown below, the following were observed:
(i) 1$\Omega$connected at port B draws a current of 3 A
(ii) 2.5 $\Omega$ connected at port B draws a current of 2 A
With 10 V dc connected at port A, the current drawn by 7 $\Omega$connected at port B is
- 3/7 A
- 5/7
- 1A
- 9/7 A
For parallel RLC circuit, which one of the following statements is NOT correct?
- The bandwidth of the circuit deceases if R is increased.
- The bandwidth of the circuit remains same if L is increased.
- At resonance, input impedance is a real quantity.
- At resonance, the magnitude of input impedance attains its minimum value.
With 10 V dc connected at port A in the linear non-reciprocal two-port network shown below, the following were observed:
(i) 1$\Omega$connected at port B draws a current of 3 A.
(ii) 2.5 $\Omega$ connected at port B draws a current of 2 A.

For the same network, with 6 V dc connected at port A, 1 $\Omega$ connected at port B draws 7/3 A. If 8 V dc is connected to port A, the open circuit voltage at port B is
- 6 V
- 7 V
- 8 V
- 9 V
The time domain behaviour of an RL circuit is represented by
L$\dfrac{d_i}{d_t} + R_i = V_0 (1 + Be^{-RT/L} sint ) \ u(t)$
For an initial current of i (0) = $\dfrac{V_0}{R}$, the steady state value of the current is given by
- i (t) $\rightarrow \dfrac{V_0}{R}$
- i (t) $\rightarrow \dfrac{2V_0}{R}$
- i (t) $\rightarrow \dfrac{V_0}{R}$(1 + B)
- i (t) $\rightarrow \dfrac{2V_0}{R}$(1 + B)
The average power delivered to an impendence (4 -j3)$\Omega$by a current 5 cos(100$\Omega$t + 100) A is
- 44.2 W
- 50 W
- 62.5 W
- 125 W
Assuming both the voltage sources are in phase, the value of R for which maximum power is transferred from circuit A to circuit B is
- 0.8 $\Omega$
- 1.4 $\Omega$
- 2$\Omega$
- 2.8 $\Omega$
For the circuit shown in the figure, the Thevenin voltage and resistance looking into X - Y are

- $\dfrac{4}{3}$V, 2$\Omega$
- 4V, $\dfrac{2}{3}$$\Omega$
- $\dfrac{4}{3}$V, $\dfrac{2}{3}$$\Omega$
- 4V, 2$\Omega$
The driving point impedance Z(s) of a network has the pole-zero locations as shown in the figure below. If Z(0) = 3, then Z(s) is

- $\dfrac{3(s+3)}{s^2 + 2s + 3}$
- $\dfrac{2(s+3)}{s^2 + 2s + 2}$
- $\dfrac{3(s-3)}{s^2 - 2s - 2}$
- $\dfrac{2(s-3)}{s^2 - 2s - 2}$
The minimum number of equations required to analyse the circuit shown in the figure below is

- 3
- 4
- 6
- 7
In the following graph, the number of trees (P) and the number of cut-set (Q) are

- P = 2 Q = 2
- P = 2 Q = 6
- P = 4 Q = 6
- P = 4 Q = 10
The equivalent inductance measured between the terminals 1 and 2 for the circuit shown in the figure is
- L1 + L2 + M
- L1 + L2 – M
- L1 + L2 + 2M
- L1 + L2 – 2M
How much current will flow in a 100 Hz series RLC circuit, if VS = 20 V, RT = 66 ohms and XT = 47 ohms?
- 1.05 A
- 303 mA
- 247 mA
- 107 mA











