Control Systems - Stability Analysis and Frequency Response
Comprehensive test covering stability analysis, frequency response, state space representation, compensator design, and root locus techniques for GATE Electronics and Communication Engineering
Questions
For the polynomial P(s) = s2 + s4 + 2s3 + 3s + 15, the number of roots which lie in the right half of the s−plane is
- 4
- 2
- 3
- 1
A system has poles at 0.1 Hz, 1 Hz and 80 Hz; zeros at 5 Hz, 100 Hz and 200 Hz.
The approximate phase of the system response at 20 Hz is
- -900
- 00
- 900
- -1800
A signal flow graph of a system is given below:

The set of equalities that corresponds to this signal flow graph is
The state space representation of a separately excited DC servo motor dynamics is given as
$
\left[
\begin{array}
\ \dfrac{d\omega}{dt} \\
\dfrac{di_s}{dt}
\end{array}
\right] =
$ $
\left[
\begin{array}
-1 & 1 \\
-1 & -10
\end{array}
\right]
$ $
\left[
\begin{array}
\ \omega \\
i_s
\end{array}
\right]
$ + $
\left[
\begin{array}
\ 0 \\
10
\end{array}
\right] u
$
- $\dfrac{10}{s^2+11s+11}$
- $\dfrac{1}{s^2+11s+11}$
- $\dfrac{10+10}{s^2+11s+11}$
- $\dfrac{1}{s^2+s+1}$
The approximate Bode magnitude plot of a minimum-phase system is shown in figure. The transfer function of the system is

- 108 $\dfrac{(s+0.1)^3}{(s+10)^2 (s+100)}$
- 107 $\dfrac{(s+0.1)^3}{(s+10) (s+100)}$
- 108 $\dfrac{(s+0.1)^2}{(s+10)^2 (s+100)}$
- 109 $\dfrac{(s+0.1)^3}{(s+10)^2 (s+100)^2}$
The positive values of “K” and “a” so that the system shown in the figure below oscillates at a frequency of 2 rad/sec respectively are

- 1, 0.75
- 2, 0.75
- 1, 1
- 2, 2
Given A= $
\left[
\begin{array}
\ 1 & 0 \\
0 & 1
\end{array}
\right]
$ the state transition matrix eAt is given by
- $ \left[ \begin{array} \ 0 & e^{-t} \\\\ e^{-t} & 0 \end{array} \right] $
- $ \left[ \begin{array} \ e^{-t} & 0 \\\\ 0 & e^t & \end{array} \right] $
- $ \left[ \begin{array} \ e^{-t} & 0 \\\\ 0 & e^{-t} & \end{array} \right] $
- $ \left[ \begin{array} \ 0 & e^{t} \\\\ e^{t} & 0 \end{array} \right] $
In the derivation of expression for peak percent overshoot, $M_p = exp
\left(
\dfrac{-\pi\xi}{\sqrt{1-\xi^2}}
\right) \times 100 %
$, which of the following conditions is not required?
- System is linear and time invariant.
- The system transfer function has a pair of complex conjugate poles and no zeroes.
- There is no transportation delay in the system.
- The system has zero initial conditions.
The state variable equations of a system are x1 = -3x1 -x2 = u, x2 = 2x1 and Y= x1+ u. The system is
- controllable but not observable
- observable but not controllable
- neither controllable nor observable
- controllable and observable
A certain system has transfer function
G (s) = $\dfrac{s+8}{s^2+\alpha s-4}$
where$\alpha$ is a parameter. Consider the standard negative unity feedback configuration as shown below:

Which of the following statements is true?
- The closed loop systems is never stable for any value of $\alpha$.
- For some positive value of $\alpha$, the closed loop system is stable, but not for all positive values.
- For all positive values of $\alpha$, the closed loop system is stable.
- The closed loop system is stable for all values of $\alpha$, both positive and negative.
The open loop transfer function of a plant is given as G(s) = $\dfrac{1}{s^2-1}$. If the plant is operated in a unity feedback configuration, the lead compensator that an stabilize this control system is
- $\dfrac{10(s-1)}{s+2}$
- $\dfrac{10(s-1)}{s+2}$
- $\dfrac{10(s+2)}{s+10}$
- $\dfrac{2(s+2)}{s+10}$
An unity feedback system is given as
$G(s) = \dfrac{K(1-s)}{s(s+3)}$
Indicate the correct root locus diagram.
The gain margin and the phase margin of a feedback system with G (s) H(s) = $\dfrac{s}{(s+100)^3}$are
- 0 dB, 0°
- $\infty$, $\infty$
- $\infty$, 0°
- 88.5 dB, $\infty$
The open-loop transfer function of a unity feedback system is
G(s) $\dfrac{K}{s(s^2+s+2)(s+3)}$
The range of K for which the system is stable is
- $\dfrac{21}{4} > K > 0$
- 13 > K > 0
- $\dfrac{21}{4}$< K < $\infty$
- – 6 < K < $\infty$










