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Test 2 - Analog Circuits (Electronics and Communication)
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In the following limiter circuit, an input voltage Vi = 10 sin 100 $\pi$t is applied. Assume that the diode drop is 0.7 V when it is forward biased. The zener breakdown voltage is 6.8 V. The maximum and minimum values of the output voltage respectively are
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A
7.5 V, - 0.7 V
💡 Explanation:
For the positive half of $V_i,$ the diode $D_1$ is forward bias, $D_2$ is reverse bias and the zener diode is in breakdown state because state because $V_i > 6.8$
Thus output voltage is $V_0 = 0.7 + 6.8 = 7.5V$
For the negative half of $V_i$, $D_2$ is forward bias thus
Then $V_0 = -0.7 V$