General Knowledge Quiz

The hour and minute hands coincide 11 times in every 12-hour period, including at noon (12:00) and at midnight (12:00). Between these two endpoints, they cross at approximately 1:05, 2:11, 3:16, 4:22, 5:27, 6:33, 7:38, 8:44, 9:49, and 10:55, which gives us 10 times. The hands move continuously, creating these crossing points approximately every 65.45 minutes.

A strawberry is unique because what appear to be 'seeds' on its surface are actually the fruits (achenes), while the fleshy part we eat is the receptacle. The true seeds are inside these achenes. Options A and D are nonsensical non-answers. Option C (avocado) has its seed inside, and option E has multiple typos ('brazlian' instead of 'Brazilian', 'boons' instead of 'nuts').

Working backwards: if 1 mango remains after 3rd guard, before 3rd guard he had (1+1)×2=4. Before 2nd guard: (4+1)×2=10. Before 1st guard: (10+1)×2=22. Each guard takes half+1, so reverse is add 1 then double. 22 is the starting amount.

At 3:15, the hour hand moves 1/4 of the way between 3 and 4 (15 minutes = 1/4 hour). Since numbers are 30° apart, the hour hand advances 7.5° from the 3. The minute hand points exactly at 3 (0° from 3). Therefore the angle between them is 7.5°. Many incorrectly assume the hour hand stays at 3 (giving 0°) or calculate full hour differences.

From 'all stooges are scrooges' and 'some stooges are troudges', we can conclude that the stooges who are troudges are also scrooges. Therefore, some scrooges are troudges. This is a valid syllogistic inference where we have an intersection between scrooges (via stooges) and troudges.

From 'all Toms can dance' and 'some Toms can sing', we know some Toms can both dance and sing. Since 'all who can dance and sing are Pats', these Toms must be Pats. Therefore, some Toms are Pats. Option A incorrectly uses 'most' which is not supported by the premises.

Since 'all cats are dogs' and 'all cats are goats', all cats belong to both the dogs and goats categories. This means cats form the intersection between dogs and goats. Therefore, some dogs (specifically the cats) are goats. This is a valid conclusion from the universal premises.

From 'all who can squeal can prick' and 'K can squeal', we can deduce that K can prick. This is direct application of a universal conditional statement. The other options cannot be logically deduced from the given premises about the relationships between squeak, prick, and squeal.

From the chain 'all knowledge is power, all power is captured, all captured is jailed', we can conclude that all knowledge ends up jailed. Since 'some jailed is freed', the freed individuals must come from the jailed group. Therefore, some freed (those who were freed) were previously jailed.