Home › Quizzes › Brahmagupta's Contributions to Trigonometry

Brahmagupta's Contributions to Trigonometry

Brahmagupta's Contributions to Trigonometry

14 Questions Published
Play Quiz Practise this topic out loud

Questions

Question 1 Multiple Choice (Single Answer)

Brahmagupta's formula for calculating the sine of an angle is given by:

  1. $\sin A = \frac{\sin \frac{A}{2}}{\cos \frac{A}{2}}$
  2. $\sin A = \frac{\sin A}{\cos A}$
  3. $\sin A = \frac{\tan A}{\sec A}$
  4. $\sin A = \frac{\cos A}{\sec A}$
Question 2 Multiple Choice (Single Answer)

Brahmagupta's formula for calculating the cosine of an angle is given by:

  1. $\cos A = \frac{\cos \frac{A}{2}}{\sin \frac{A}{2}}$
  2. $\cos A = \frac{\cos A}{\sin A}$
  3. $\cos A = \frac{\tan A}{\csc A}$
  4. $\cos A = \frac{\sin A}{\csc A}$
Question 3 Multiple Choice (Single Answer)

Brahmagupta's formula for calculating the tangent of an angle is given by:

  1. $\tan A = \frac{\sin A}{\cos A}$
  2. $\tan A = \frac{\cos A}{\sin A}$
  3. $\tan A = \frac{\sin A}{\sec A}$
  4. $\tan A = \frac{\cos A}{\csc A}$
Question 4 Multiple Choice (Single Answer)

Brahmagupta's formula for calculating the cotangent of an angle is given by:

  1. $\cot A = \frac{\cos A}{\sin A}$
  2. $\cot A = \frac{\sin A}{\cos A}$
  3. $\cot A = \frac{\cos A}{\sec A}$
  4. $\cot A = \frac{\sin A}{\csc A}$
Question 5 Multiple Choice (Single Answer)

Brahmagupta's formula for calculating the secant of an angle is given by:

  1. $\sec A = \frac{1}{\cos A}$
  2. $\sec A = \frac{\cos A}{\sin A}$
  3. $\sec A = \frac{\sin A}{\cos A}$
  4. $\sec A = \frac{\cos A}{\sec A}$
Question 6 Multiple Choice (Single Answer)

Brahmagupta's formula for calculating the cosecant of an angle is given by:

  1. $\csc A = \frac{1}{\sin A}$
  2. $\csc A = \frac{\sin A}{\cos A}$
  3. $\csc A = \frac{\cos A}{\sin A}$
  4. $\csc A = \frac{\sin A}{\csc A}$
Question 7 Multiple Choice (Single Answer)

Brahmagupta's formula for calculating the sine of the sum of two angles is given by:

  1. $\sin(A + B) = \sin A \cos B + \cos A \sin B$
  2. $\sin(A + B) = \sin A \sin B + \cos A \cos B$
  3. $\sin(A + B) = \tan A \sec B + \cot A \csc B$
  4. $\sin(A + B) = \cos A \sec B + \sin A \csc B$
Question 8 Multiple Choice (Single Answer)

Brahmagupta's formula for calculating the cosine of the sum of two angles is given by:

  1. $\cos(A + B) = \cos A \cos B - \sin A \sin B$
  2. $\cos(A + B) = \cos A \sin B + \sin A \cos B$
  3. $\cos(A + B) = \tan A \sec B - \cot A \csc B$
  4. $\cos(A + B) = \sin A \sec B + \cos A \csc B$
Question 9 Multiple Choice (Single Answer)

Brahmagupta's formula for calculating the tangent of the sum of two angles is given by:

  1. $\tan(A + B) = \frac{\tan A + \tan B}{1 - \tan A \tan B}$
  2. $\tan(A + B) = \frac{\tan A - \tan B}{1 + \tan A \tan B}$
  3. $\tan(A + B) = \frac{\sin A + \sin B}{\cos A + \cos B}$
  4. $\tan(A + B) = \frac{\cos A + \cos B}{\sin A + \sin B}$
Question 10 Multiple Choice (Single Answer)

Brahmagupta's formula for calculating the cotangent of the sum of two angles is given by:

  1. $\cot(A + B) = \frac{\cot A \cot B - 1}{\cot A + \cot B}$
  2. $\cot(A + B) = \frac{\cot A \cot B + 1}{\cot A - \cot B}$
  3. $\cot(A + B) = \frac{\sin A - \sin B}{\cos A - \cos B}$
  4. $\cot(A + B) = \frac{\cos A - \cos B}{\sin A - \sin B}$
Question 11 Multiple Choice (Single Answer)

Brahmagupta's formula for calculating the sine of the difference of two angles is given by:

  1. $\sin(A - B) = \sin A \cos B - \cos A \sin B$
  2. $\sin(A - B) = \sin A \sin B + \cos A \cos B$
  3. $\sin(A - B) = \tan A \sec B - \cot A \csc B$
  4. $\sin(A - B) = \cos A \sec B + \sin A \csc B$
Question 12 Multiple Choice (Single Answer)

Brahmagupta's formula for calculating the cosine of the difference of two angles is given by:

  1. $\cos(A - B) = \cos A \cos B + \sin A \sin B$
  2. $\cos(A - B) = \cos A \sin B - \sin A \cos B$
  3. $\cos(A - B) = \tan A \sec B + \cot A \csc B$
  4. $\cos(A - B) = \sin A \sec B + \cos A \csc B$
Question 13 Multiple Choice (Single Answer)

Brahmagupta's formula for calculating the tangent of the difference of two angles is given by:

  1. $\tan(A - B) = \frac{\tan A - \tan B}{1 + \tan A \tan B}$
  2. $\tan(A - B) = \frac{\tan A + \tan B}{1 - \tan A \tan B}$
  3. $\tan(A - B) = \frac{\sin A - \sin B}{\cos A - \cos B}$
  4. $\tan(A - B) = \frac{\cos A - \cos B}{\sin A - \sin B}$
Question 14 Multiple Choice (Single Answer)

Brahmagupta's formula for calculating the cotangent of the difference of two angles is given by:

  1. $\cot(A - B) = \frac{\cot A \cot B + 1}{\cot A - \cot B}$
  2. $\cot(A - B) = \frac{\cot A \cot B - 1}{\cot A + \cot B}$
  3. $\cot(A - B) = \frac{\sin A + \sin B}{\cos A + \cos B}$
  4. $\cot(A - B) = \frac{\cos A + \cos B}{\sin A + \sin B}$
← Back to Quizzes