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What is the limit of the function $f(x) = \frac{x^2 - 4}{x - 2}$ as $x$ approaches 2?
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A
4
💡 Explanation:
To find the limit, we can factor the numerator and cancel the common factor of $(x - 2)$ in the numerator and denominator. This gives $\lim_{x \to 2} \frac{x^2 - 4}{x - 2} = \lim_{x \to 2} \frac{(x + 2)(x - 2)}{x - 2} = \lim_{x \to 2} (x + 2) = 2 + 2 = 4$.