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William Lowell Putnam Mathematical Competition
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Let (f(x) = x^3 - 3x^2 + 2x + 1). Find the value of (f(f(1))).
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A
1
💡 Explanation:
Given (f(x) = x^3 - 3x^2 + 2x + 1), we have (f(1) = 1^3 - 3(1)^2 + 2(1) + 1 = -1). Therefore, (f(f(1)) = f(-1) = (-1)^3 - 3(-1)^2 + 2(-1) + 1 = 1).