Consider the following piece of code: 1 long i = 2 ; 2 switch (i) { 3 case 1: 4 System.out.println ("Case 1"); 5 case 2: 6 System.out.println ("Case 2"); 7 case 3: 8 System.out.println ("Case 3"); 9 default: 10 System.out.println ("Default"); 11 } Which of the following lines will be included in the output? (Choose all that apply, please bear with code as formating it sems is not possible,first numbers represent line numbers)

In Java the compiler will always insert a default , no argument constructor into any class definition

In Java if an arithmetic operation is performed then , In case the operands are of different types the resulting type is always the widest of two types

consider the following scenarioint i = 0;if ( i ) {System.out.println("This won't print");}else{System.out.println("This prints");}

In the following code variable test would be created on? static int test;

In the following code variable test1 would be allocated memory on?int func(){int test1 = 10;return test1;}void main(){ int i = 0; i = func();}

Can we change the content of string letral?

The following code is compiled: double abc = 100.0; double xyz = abc/0; What is the result?

Overloaded methods should not throw new checked exceptions that have not been thrown by the original method?

Consider the following case: A = false B = true; What is the result of A && B ?

Consider the following case; int i; int k; for(i=0;k<10;i++){/* The body */} This will not compile?