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To solve the equation, we can use the quadratic formula: (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}). Plugging in the values of (a = 1, b = -5, c = 6), we get: (x = \frac{-(-5) \pm \sqrt{(-5)^2 - 4(1)(6)}}{2(1)}) = \frac{5 \pm \sqrt{25 - 24}}{2} = \frac{5 \pm 1}{2} = 2, 3).