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Java Programming Fundamentals
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What is the output of the following code when compiled and run? Select one correct answer. public class Question02 { public static void main(String[] args){ int j = 017; int i = (byte)j >> 2; //line 1 System.out.println(Integer.toBinaryString(i)); //line 2 } }
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A
Prints 11
💡 Explanation:
017 is an octal literal in Java, equal to decimal 15. The (byte) cast doesn't change the value since 15 fits in a byte. Right-shifting 15 (binary 1111) by 2 positions gives 3 (binary 11). Integer.toBinaryString(3) outputs '11'.