Which of the following is not a task in Workflow Manager

Which of the following is/are an Active transformation

What types of data source(s) can be read with the source qualifier transformation?

Which activities below can be performed using Designer

Choose the correct option - Transformations which have only Input/Output ports

How many sources can be joined using Joiner transformation

Which are the different Lookup cache types

Which transformation is used to read data from Cobol files?

What are the types of lookup

What are the views available in the Workflow Monitor

Which of the following are Informatica PowerCenter Server Components

Which datatype cannot be converted to any other datatype

Which one of the transformations below does not use index and data cache

Repository Manager is used to

1 options linesize=80; 2 title 'Example 2. Test of proc freq'; 3 4 proc format; 5 value $fsex '1'='Male' 6 '2'='Female'; NOTE: Format $FSEX has been output. 7 run; NOTE: PROCEDURE FORMAT used: real time 0.28 seconds cpu time 0.04 seconds 8 9 data sample1; 10 infile 'example2.dat'; 11 input caseid 1-4 mathsat 6-8 score 10-11 sex $ 13 teach 15 12 format sex $fsex.; ______ ______ ______ 228 228 228 13 label caseid='Subject Number' 14 mathsat='SAT Math Score' 15 score='Final Calculus Score' 16 sex='Sex of Participant' 17 teach='Student Rated Teaching Ability'; 18 ERROR 228-185: Informat $FSEX is unknown. ERROR 228-185: Informat $FSEX is unknown. ERROR 228-185: Informat $FSEX is unknown. NOTE: The SAS System stopped processing this step because of errors. NOTE: SAS set option OBS=0 and will continue to check statements. This may cause NOTE: No observations in data set. WARNING: The data set WORK.SAMPLE1 may be incomplete. When this step was stopped there were 0 observations and 6 variables. What is the problem?

void main() { int i = 10; int *p=&i; p++; printf("%d",(p-&i)); }

Which of the following are valid statements in IDEAL?

void main() { int i = 10; long *p=&i; p++; printf("%d",(p-&i)); }

void main() { int i = 10; long *p=&i; p++; printf("%d",abs(&i-p)); }