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Putnam Mathematical Competition
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Let $f(x)$ be a continuous function on the interval $[0, 1]$. If $f(0) = 0$ and $f(1) = 1$, then there exists a point $c$ in the interval $(0, 1)$ such that $f(c) = c$.
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A
True
💡 Explanation:
This is a consequence of the Intermediate Value Theorem.