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Differential Equations in Physics
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A particle moves in a straight line with a velocity given by the function (v(t) = 3t^2 - 2t + 1). What is the particle's acceleration at time (t = 2) seconds?
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A
\(6\)
💡 Explanation:
The acceleration of the particle is the derivative of the velocity function with respect to time. So, (a(t) = v'(t) = 6t - 2). At time (t = 2) seconds, the acceleration is (a(2) = 6(2) - 2 = 10) m/s^2.