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programming languages Online Quiz - 44

Description: programming languages Online Quiz - 44
Number of Questions: 20
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Tags: programming languages

What gets printed? my $a = 123; my $b = 0123; if ($a == $b) { print "same"; } else { print "different"; }

  1. same

  2. different

  3. the code is ill-formed

  4. None of the above

Answer: 2

What will be the value of $val? my $str = 'aa bb cccc'; my $val = () = $str =~ /\w+/g;

  1. undef

  2. aa

  3. cccc

  4. 3

  5. 0

Answer: 4

What will be printed by the following code? package A; sub new { return bless {}; } sub foo { return 'A'; } package B; use base 'A'; sub foo { return 'B'; } package main; my $obj = B->new(); print $obj->foo(), "\n";

  1. A

  2. B

  3. the code will fail

  4. None of the above

Answer: 1

What will be printed by the code below? my $val = 'x'; print ref($val);

  1. SCALAR

  2. empty value

  3. STRING

  4. "not a reference"

Answer: 2
  1. public class Wind { 4. public static void main(String[] args) { 5. foreach: 6. for(int j=0; j<5; j++) { 7. for(int k=0; k< 3; k++) { 8. System.out.print(" " + j); 9. if(j==3 && k==1) break foreach; 10. if(j==0 || j==2) break; 11. } 12. } 13. } 14. }
  1. 0 1 2 3

  2. 1 1 1 3 3

  3. 0 1 1 1 2 3 3

  4. 1 1 1 3 3 4 4 4

  5. 0 1 1 1 2 3 3 4 4 4

  6. compilation fails

Answer: 3

Given: 3. public class Circles { 4. public static void main(String[] args) { 5. int[] ia = {1,3,5,7,9}; 6. for(int x : ia) { 7. for(int j = 0; j < 3; j++) { 8. if(x > 4 && x < 8) continue; 9. System.out.print(" " + x); 10. if(j == 1) break; 11. continue; 12. } 13. continue; 14. } 15. } 16. }

  1. 1 3 9

  2. 5 5 7 7

  3. 1 3 3 9 9

  4. 1 1 3 3 9 9

  5. 1 1 1 3 3 3 9 9 9

  6. Compilation fails

Answer: 4
  1. class Loopy { 2. public static void main(String[] args) { 3. int[] x = {7,6,5,4,3,2,1}; 4. // insert code here 5. System.out.print(y + " "); 6. } 7. } }
  1. for(int y : x) {

  2. for(x : int y) {

  3. int y = 0; for(y : x) {

  4. for(int y=0, z=0; z

  5. for(int y=0, int z=0; z

  6. int y = 0; for(int z=0; z

Answer: 1,4,6

class Plane { static String s = "-"; public static void main(String[] args) { new Plane().s1(); System.out.println(s); } void s1() { try { s2(); } catch (Exception e) { s += "c"; } } void s2() throws Exception { s3(); s += "2"; s3(); s += "2b"; } void s3() throws Exception { throw new Exception(); } }

  1. -

  2. -c

  3. -c2

  4. -2c

  5. -c22b

  6. -2c2b

Answer: 2

public abstract class AbstractTest { public int getNum() { return 45; } public abstract class Bar { public int getNum() { return 38; } } public static void main(String[] args) { AbstractTest t = new AbstractTest() { public int getNum() { return 22; } }; AbstractTest.Bar f = t.new Bar() { public int getNum() { return 57; } }; System.out.println(f.getNum() + " " + t.getNum()); } }

  1. 57 22

  2. 45 38

  3. 45 57

  4. D. An exception occurs at runtime

Answer: 2

Which of the below symbol is used to make comments in C language?

  1. //

  2. #

  3. !!

Answer: 2

Can a variable be declared as both const and volatile

  1. True

  2. False

Answer: 1

#include main (){ char c[] = "Hello"; char *p = "Hello"; printf("Size of c: %d Addr of c:%x\n",sizeof(c),c); }

  1. Size of c: some value Addr of c:some address

  2. Size of c: some value Addr of c:some value

  3. Size of c: some address Addr of c:some address

  4. Compilation error

Answer: 4

main() { int a[5] = {10,20,30,40,50}; char *p; p=(char *)a; printf("%d\n",a); }

  1. some value

  2. compilation error

  3. 10

  4. 50

Answer: 1

#include main(){ int a=2; int p=&a; print("%x\t",p); print("%x\t",p++); print("%x\t",p); }

  1. someaddress value someaddress

  2. value value value

  3. syntax error

  4. compilation error

Answer: 3

#include main(){ static int a[20]; int i=0; a[i]=i++; printf("%d %d %d",a[0],a[1],i); }

  1. 0 0 0

  2. 0 1 0

  3. 0 0 1

  4. 0 1 1

Answer: 3

#include main(){ extern int i; i=23; printf("%d",i); }

  1. 23

  2. Prints some address

  3. Compilation error

  4. Run time error

Answer: 3

#include main (){ unsigned int a = 0xf0ad; char c = (char *) &a; printf("value @c: %x",c); }

  1. value @c: ffffffad

  2. value @c: 0xf0ad

  3. compilation error

  4. syntax error

Answer: 1

#include main() { int a[2][2][2] = {{10,2,3,4},{5,6,7,8}}; int p,*q; p=&a[2][2][2]; *q=*a printf("%d----%d",p,*q); }

  1. Compilation error

  2. syntax error

  3. 10 2 3 4 5 6 7 8

  4. print the address of pointer p and q

Answer: 1

#include main() { char a[4]="HELLO"; printf("%s",a); }

  1. O

  2. H

  3. HELLO

  4. Compilation Error

Answer: 4

Encapsulation is the process of basing one class on another.

  1. True

  2. False

Answer: 2
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