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programming languages Online Quiz - 44

Description: programming languages Online Quiz - 44
Number of Questions: 20
Created by:
Tags: programming languages
Attempted 0/20 Correct 0 Score 0

#include main() { int a[2][2][2] = {{10,2,3,4},{5,6,7,8}}; int p,*q; p=&a[2][2][2]; *q=**a printf("%d----%d",*p,*q); }

  1. Compilation error

  2. syntax error

  3. 10 2 3 4 5 6 7 8

  4. print the address of pointer p and q


Correct Option: A
  1. 23

  2. Prints some address

  3. Compilation error

  4. Run time error


Correct Option: C

#include main(){ static int a[20]; int i=0; a[i]=i++; printf("%d %d %d",a[0],a[1],i); }

  1. 0 0 0

  2. 0 1 0

  3. 0 0 1

  4. 0 1 1


Correct Option: C
  1. someaddress value someaddress

  2. value value value

  3. syntax error

  4. compilation error


Correct Option: C
  1. Size of c: some value Addr of c:some address

  2. Size of c: some value Addr of c:some value

  3. Size of c: some address Addr of c:some address

  4. Compilation error


Correct Option: D

Can a variable be declared as both const and volatile

  1. True

  2. False


Correct Option: A

class Plane { static String s = "-"; public static void main(String[] args) { new Plane().s1(); System.out.println(s); } void s1() { try { s2(); } catch (Exception e) { s += "c"; } } void s2() throws Exception { s3(); s += "2"; s3(); s += "2b"; } void s3() throws Exception { throw new Exception(); } }

  1. -

  2. -c

  3. -c2

  4. -2c

  5. -c22b

  6. -2c2b


Correct Option: B
  1. class Loopy { 2. public static void main(String[] args) { 3. int[] x = {7,6,5,4,3,2,1}; 4. // insert code here 5. System.out.print(y + " "); 6. } 7. } }
  1. for(int y : x) {

  2. for(x : int y) {

  3. int y = 0; for(y : x) {

  4. for(int y=0, z=0; z

  5. for(int y=0, int z=0; z

  6. int y = 0; for(int z=0; z


Correct Option: A,D,F
  1. public class Wind { 4. public static void main(String[] args) { 5. foreach: 6. for(int j=0; j<5; j++) { 7. for(int k=0; k< 3; k++) { 8. System.out.print(" " + j); 9. if(j==3 && k==1) break foreach; 10. if(j==0 || j==2) break; 11. } 12. } 13. } 14. }
  1. 0 1 2 3

  2. 1 1 1 3 3

  3. 0 1 1 1 2 3 3

  4. 1 1 1 3 3 4 4 4

  5. 0 1 1 1 2 3 3 4 4 4

  6. compilation fails


Correct Option: C

What will be the value of $val? my $str = 'aa bb cccc'; my $val = () = $str =~ /\w+/g;

  1. undef

  2. aa

  3. cccc

  4. 3

  5. 0


Correct Option: D
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