SNAP Quantitative Aptitude Practice

In the given code language, each letter is assigned a numerical value based on its position in the alphabet. For example, 'B' is assigned 2, 'O' is assigned 15, and so on. To encode 'DESK', we add the numerical values of each letter: 4 (D) + 5 (E) + 19 (S) + 11 (K) = 39. Therefore, 'DESK' is written as '30512' in that code language.

To find the time at which the two trains meet, we need to calculate the total time taken by both trains to cover the distance between Mumbai and Delhi. The first train travels for 1 hour before the second train leaves Delhi. Therefore, the first train covers a distance of 60 km in 1 hour. The second train travels for 5 hours (from 11:00 AM to 4:00 PM) and covers a distance of 75 km/h * 5 h = 375 km. The total distance covered by both trains is 60 km + 375 km = 435 km. Since the total distance between Mumbai and Delhi is 1350 km, the two trains will meet when they have covered 435 km. Therefore, the two trains will meet at 4:00 PM.

Initially, there are 60 men and 40 women in the company. After 20% of the men and 30% of the women leave, the number of men remaining is 60 - (20% of 60) = 48, and the number of women remaining is 40 - (30% of 40) = 28. Therefore, the total number of remaining employees is 48 + 28 = 76. The percentage of women among the remaining employees is (28 / 76) * 100 = 44%.

Let the cost price of the article be (x). Selling price at a profit of 20% = (x + 20% of x = \frac{6}{5}x). Selling price at a loss of 4% = (x - 4% of x = \frac{24}{25}x). Equating the two selling prices, we get (\frac{6}{5}x = \frac{24}{25}x). Solving for (x), we get (x = \frac{120}{100}) of the cost price.

Speed = Distance / Time. To find the speed of the train, we need to convert the distances and times to the same units. Converting 100 meters to kilometers: 100 meters = 0.1 kilometers. Converting 200 meters to kilometers: 200 meters = 0.2 kilometers. Converting 10 seconds to hours: 10 seconds = 10/3600 hours = 1/360 hours. Converting 30 seconds to hours: 30 seconds = 30/3600 hours = 1/120 hours. Speed of the train when crossing the platform = 0.1 km / (1/360) h = 36 km/h. Speed of the train when crossing the bridge = 0.2 km / (1/120) h = 24 km/h. Average speed of the train = (36 km/h + 24 km/h) / 2 = 30 km/h. Converting 30 km/h to km/h: 30 km/h = 30 * 18/5 km/h = 88 km/h.

Simple Interest = (Principal * Rate * Time) / 100. Let the principal be (P) and the rate of interest be (R%). In 2 years, the amount becomes (\frac{13}{12}P). Therefore, (\frac{13}{12}P = P + (P * R * 2) / 100). Simplifying the equation, we get (R = 12%.

Initially, there are 60% * 1200 = 720 male employees and 40% * 1200 = 480 female employees. After 20% of the male employees and 30% of the female employees leave, the number of male employees remaining is 720 - (20% of 720) = 576, and the number of female employees remaining is 480 - (30% of 480) = 336. Therefore, the total number of employees remaining is 576 + 336 = 888.

To find the time at which the two trains meet, we need to calculate the total time taken by both trains to cover the distance between Mumbai and Delhi. The first train travels for 1 hour before the second train leaves Delhi. Therefore, the first train covers a distance of 60 km in 1 hour. The second train travels for 5 hours (from 11:00 AM to 4:00 PM) and covers a distance of 75 km/h * 5 h = 375 km. The total distance covered by both trains is 60 km + 375 km = 435 km. Since the total distance between Mumbai and Delhi is 1350 km, the two trains will meet when they have covered 435 km. Therefore, the two trains will meet at 4:00 PM.

Let the cost price of the article be (x). Selling price at a profit of 20% = (x + 20% of x = \frac{6}{5}x). Selling price at a loss of 4% = (x - 4% of x = \frac{24}{25}x). Equating the two selling prices, we get (\frac{6}{5}x = \frac{24}{25}x). Solving for (x), we get (x = \frac{120}{100}) of the cost price.

Speed = Distance / Time. To find the speed of the train, we need to convert the distances and times to the same units. Converting 100 meters to kilometers: 100 meters = 0.1 kilometers. Converting 200 meters to kilometers: 200 meters = 0.2 kilometers. Converting 10 seconds to hours: 10 seconds = 10/3600 hours = 1/360 hours. Converting 30 seconds to hours: 30 seconds = 30/3600 hours = 1/120 hours. Speed of the train when crossing the platform = 0.1 km / (1/360) h = 36 km/h. Speed of the train when crossing the bridge = 0.2 km / (1/120) h = 24 km/h. Average speed of the train = (36 km/h + 24 km/h) / 2 = 30 km/h. Converting 30 km/h to km/h: 30 km/h = 30 * 18/5 km/h = 88 km/h.

Simple Interest = (Principal * Rate * Time) / 100. Let the principal be (P) and the rate of interest be (R%). In 2 years, the amount becomes (\frac{13}{12}P). Therefore, (\frac{13}{12}P = P + (P * R * 2) / 100). Simplifying the equation, we get (R = 12%.

Initially, there are 60% * 1200 = 720 male employees and 40% * 1200 = 480 female employees. After 20% of the male employees and 30% of the female employees leave, the number of male employees remaining is 720 - (20% of 720) = 576, and the number of female employees remaining is 480 - (30% of 480) = 336. Therefore, the total number of employees remaining is 576 + 336 = 888.

To find the time at which the two trains meet, we need to calculate the total time taken by both trains to cover the distance between Mumbai and Delhi. The first train travels for 1 hour before the second train leaves Delhi. Therefore, the first train covers a distance of 60 km in 1 hour. The second train travels for 5 hours (from 11:00 AM to 4:00 PM) and covers a distance of 75 km/h * 5 h = 375 km. The total distance covered by both trains is 60 km + 375 km = 435 km. Since the total distance between Mumbai and Delhi is 1350 km, the two trains will meet when they have covered 435 km. Therefore, the two trains will meet at 4:00 PM.

Let the cost price of the article be (x). Selling price at a profit of 20% = (x + 20% of x = \frac{6}{5}x). Selling price at a loss of 4% = (x - 4% of x = \frac{24}{25}x). Equating the two selling prices, we get (\frac{6}{5}x = \frac{24}{25}x). Solving for (x), we get (x = \frac{120}{100}) of the cost price.

Speed = Distance / Time. To find the speed of the train, we need to convert the distances and times to the same units. Converting 100 meters to kilometers: 100 meters = 0.1 kilometers. Converting 200 meters to kilometers: 200 meters = 0.2 kilometers. Converting 10 seconds to hours: 10 seconds = 10/3600 hours = 1/360 hours. Converting 30 seconds to hours: 30 seconds = 30/3600 hours = 1/120 hours. Speed of the train when crossing the platform = 0.1 km / (1/360) h = 36 km/h. Speed of the train when crossing the bridge = 0.2 km / (1/120) h = 24 km/h. Average speed of the train = (36 km/h + 24 km/h) / 2 = 30 km/h. Converting 30 km/h to km/h: 30 km/h = 30 * 18/5 km/h = 88 km/h.