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To solve the equation (x^2 + 2x - 3 = 0), we can use the quadratic formula: (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}). Substituting the values of a, b, and c into the formula, we get: (x = \frac{-2 \pm \sqrt{2^2 - 4(1)(-3)}}{2(1)}) = \frac{-2 \pm \sqrt{4 + 12}}{2} = \frac{-2 \pm \sqrt{16}}{2} = \frac{-2 \pm 4}{2} = 1 or -3). Therefore, the value of x is 1.