To answer this question, you need to understand memory allocation in C.

Let's go through each option to understand why it is correct or incorrect:

Option A) int *ptr = (int *) malloc(10, sizeof(int)); This option is incorrect because the malloc function takes only one argument, which is the number of bytes to allocate. The correct syntax would be malloc(10*sizeof(int)) instead of malloc(10, sizeof(int)).

Option B) int *ptr = (int *) calloc(10, sizeof(int)); This option is correct. The calloc function allocates memory for an array of elements and initializes them to zero. It takes two arguments: the number of elements to allocate and the size of each element. In this case, calloc(10, sizeof(int)) allocates enough space for 10 integers and initializes them to 0.

Option C) int *ptr = (int *) malloc(10*sizeof(int)); This option is correct. The malloc function allocates memory for an array of elements without initializing them. It takes one argument: the number of bytes to allocate. In this case, malloc(10*sizeof(int)) allocates enough space for 10 integers.

Option D) int *ptr = (int *) alloc(10*sizeof(int)); This option is incorrect because there is no standard function called alloc() in C. The correct function to use for memory allocation is malloc().

The correct answer is Option C. This option allocates enough space to hold an array of 10 integers that are initialized to 0.

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• Wrong explanation

To answer this question, let's go through each option to understand why it is correct or incorrect:

Option A) It will not compile. This option is incorrect. The code provided will compile without any errors.

Option B) It will print out: i=9. This option is incorrect. The program will not print "i=9" because the increment function is not modifying the global variable i. It is modifying a local variable i within the function.

Option C) It will print out: i=10. This option is incorrect for the same reason as Option B. The local variable i within the increment function is being modified, not the global variable i.

Option D) It will loop indefinitely. This option is correct. The program will enter an infinite loop because the increment function is called within the for loop condition, but it is not actually modifying the global variable i. Therefore, i will always remain 0, and the condition i < 10 will always be true.

The correct answer is D. It will loop indefinitely because the increment function is not modifying the global variable i.

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To properly initialize the variable t with the current time, you can use the time() function from the ctime library.

Option A) t = ctime(); - This option is incorrect because the ctime() function returns a string representation of the current time, not the actual time value.

Option B) time( &t ); - This option is correct because it calls the time() function and passes the address of t as an argument, allowing time() to store the current time value in t.

Option C) t = localtime(); - This option is incorrect because the localtime() function converts a time value into a broken-down time structure, not the current time.

Option D) t = clock(); - This option is incorrect because the clock() function measures the processor time, not the current time.

The correct answer is Option B.

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To find the value of z in the given code, let's break down the expression step by step:

1. x++ increments the value of x by 1 after it is used in the expression. So, the value of x is now 6.

2. --y decrements the value of y by 1 before it is used in the expression. So, the value of y is now -11.

3. y * b multiplies the value of y (-11) by the value of b (2), resulting in -22.

4. -22 / a divides the value of -22 by the value of a (4), resulting in -5.5.

5. Finally, z = 6 - (-5.5), which simplifies to z = 6 + 5.5. Therefore, z equals 11.5.

However, since the given variables are integers, the result will be truncated to the nearest integer. So, z will contain the value 11.

Therefore, the correct answer is option C) 11.

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• Wrong explanation