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Exterior angles of polygon - class-VII
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The interior angle of a regular polygon is double the exterior angle. Then the number in the polygon is
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A
$6$
💡 Explanation:
Let the number of sides in the polygon is $n$
Let the measure of exterior angles be $x$ respectively.
$\therefore$ Measure of interior angle $=2x$
So,
$\Rightarrow$ $n\times 2x=(2n-4)\times 90^o$
$\Rightarrow$ $nx=(n-2)\times 90^o$ ----- ( 1 )
Again we know that,
$\Rightarrow$ $nx=360^o$
$\Rightarrow$ $(n-2)\times 90^o=360^o$ [ From ( 1 ) ]
$\Rightarrow$ $n-2=4$
$\Rightarrow$ $n=6$
$\therefore$ The number of sides in the polygon are $6.$