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Observing space: telescopes - class-VIII
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The angular resolution of a 10cm diameter telescope at a wavelength of $5000 A^0$ is of the order of -
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A
$10^{-6} rad$
💡 Explanation:
Given parameters are,
Wavelength $\lambda = 5000\ A^{\circ}$
= $5000 \times 10^{-10}$
Diameter of telescope, $D = 10 cm = 0.1 m$
Now, Angular resolution (d\theta) formula for telescope is,
$d\theta =\dfrac{1.22 \lambda}{D}\\$
Substituting the values, we get
$\Rightarrow d\theta = \dfrac{1.22 \times 5000 \times 10^{-10}}{0.1}= 6.1 \times 10^{-6}\\$
Clearly it is having significance order of $10^{-6}$.
Thus option B is correct.