🎴 Flashcard Mode
Measuring thermal quantities by the method of mixtures - class-XI
Card1 / 71
Mastered0
Review0
QuestionClick to flip
How much heat is required to raise the temperature of 150 g of iron from $20 ^oC$ to $25 ^oC$? (Specific heat of iron $480 J kg^{-1} {;}^oC^{-1})$
AnswerClick to flip back
A
360 J
💡 Explanation:
Given $m=150$
$g=\frac {150}{1000}=0.15 kg$
Specific heat of iron
$C=480 J kg^{-1} {;}^oC^{-1})$
$\Delta =(25-20)^oC=5^oC$
$Q=m\times C\times \Delta T$
$=0.15 kg\times 480 J kg^{-1} {;}^oC^{-1}\times 5^oC$
$=360 J$.