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Square Roots and Perfect Squares
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QuestionClick to flip
The value of $\sqrt{\dfrac{64x^{2}}{49y^{2}}}$ is
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A
$\dfrac {8x}{7y}$
💡 Explanation:
$\sqrt{\dfrac{64x^{2}}{49y^{2}}}$
$\Rightarrow$ $\sqrt{\dfrac{(8x)^2}{(7y)^2}}$
Taking square root on both sides,
$\Rightarrow$ $\dfrac{8x}{7y}$
$\therefore$ $\sqrt{\dfrac{64x^{2}}{49y^{2}}}=\dfrac{8x}{7y}$