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Calculations and mental strategies 1 - class-VIII
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Four years ago, the father's age was three times the age of his son. The total of the age of the father and the son after four years will be $64$ years. What is the father's age at present?
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A
$40$ years
💡 Explanation:
fathers present age $= x$ years.
sons present age $= y$ years.
four years ago, fathers age $=3 \times $ sons age.
$(x-4)=(y-4)\times 3$
$x=3y-8$.....(i)
after 4 years, fathers age$ +$ sons age $= 64 $
$x+4+y+4=64 $
$x+y=56$.....(ii)
solve for $x$
$x=3\times 56-3x-8$
$4x=160$
$x=40$ years
D is correct.