### Measurement of properties - class-XI

 Description: measurement of properties Number of Questions: 109 Created by: Ratna Goswami Tags: matter around us chemistry some basic concepts of chemistry basic concepts of chemistry stoichiometry
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Which of the following measures pressure?

1. Barometer

2. Thermometer

3. Pycnometer

4. Parameter

5. Pressometer

Correct Option: A
Explanation:

A barometer is a scientific instrument used in meteorology to measure atmospheric pressure. Pressure tendency can forecast short term changes in the weather. Numerous measurements of air pressure are used within surface weather analysis to help find surface troughs, high pressure systems and frontal boundaries.

Which units of pressure are needed if you are going to use 0.0821 as your ideal gas constant?

1. Atmospheric

2. Torr

3. Psi

4. mmHg

5. Pascals

Correct Option: A
Explanation:

Gas constant = $0.0821$  $L atm K^{−1} mol^{−1}$

atm ( Atmospheric unit is used )

Hence the correct option is A.

Temperature is a measure of :

1. the average kinetic energy of the particles in a substance.

2. the average potential energy of the particles in a substance.

3. the highest amount of kinetic energy the particles in a substance have.

4. the number of particles a substance has.

5. the amount of heat a substance has.

Correct Option: A,E
Explanation:

Temperature is a measure of the average kinetic energy of the particles in a substance.

As the average kinetic energy of the particles in a gas is proportional to the temperature of the gas.

Hence the correct options are A and E.

Value of Plank's constant is equal to:

1. $6.625 \times 10^{-34}$ J. sec.

2. $6.25 \times 10^{-34}$ J. sec.

3. $662.5 \times 10^{-34}$ J. sec.

4. none of these

Correct Option: A
Explanation:

The Planck's constant is named after the physicist Max Planck. It links the frequency of the electromagnetic wave of a photon to its amount of energy.

$E=hv$
$h\rightarrow$ planck's constant $=6.625\times 10^{-34} J.sec.$

How many seconds are there in 3 days?

1. 259200 s

2. 172800 s

3. 24800 s

4. 72000 s

Correct Option: A
Explanation:

$1\ min=60\ s$

$1 h = 60 min = 60 \times 60 s=3600\ s$
$1 day =24\ h=24 \times 3600\ s=86400\ s$
$3 days =3 \times 86400\ s=259200\ s$
option A is correct

The least count of burette used normally is $x$ (in mL). The value of $10x$ is:

1. 1

2. 1.5

3. 0.10

4. none of these

Correct Option: A
Explanation:

Normally least count of burette is $0.10 cm^3$.

So value of $10 x=10\times0.10=1$

What should be the volume of the milk (in $m^3$) which measures 5 L?

1. $5 \times 10^{-3} m^{3}$

2. $5 \times 10^{3} m^{3}$

3. $5 \times 1000 \ m^{3}$

4. $5 \times 10^{6} m^{3}$

Correct Option: A
Explanation:
$1\ L=10^{-3}\ m^{3}$
Since 1 L = 1000 $cm^3$ and 1 m = 100 cm
$\dfrac {1 m}{100 cm} = 1 = \dfrac{100 cm}{1 m}, or (\dfrac {1 m}{100 cm})^3 = \dfrac{1m^3}{10^6cm^3}$ = $1^3$ = 1

Therefore $5\ L=5 \times 10^{-3}\ m^{3}$
option A is correct

Which of the following is not a basic physical quantity?

1. Length

2. Time

3. Density

4. Amount of substance

Correct Option: C
Explanation:

Basic physical quantities are those that are physical fundamental units. There are seven basic fundamental quantities: Length, mass, time, electric current, amount of substance, luminous intensity & temperature. The quantities which are derived with the help of these basic physical quantities are called derived quantities. They are density, volume, pressure, force, etc.

Which of the following is the non- derived unit?

1. Time

2. Mass

3. Length

4. All of the above

Correct Option: D
Explanation:

Non-derived units or fundamental units are the units which are used to derive other units. The fundamental units are length, mass, temperature, time, electric current, liminous & mole.

Match the following combinations of electrical units with their terms as single unit:

Electrical unit Single unit
(I) ampere-second A. coulomb
(II) volt-ampere B. ohm
(III) volt-ampere$^{-1}$ C. ampere
(IV) walt/ampere ohm D. watt
(V) joule / ampere second E. volt
1. A- I B-III C-IV D-II E-V

2. A- I B-II C-III D-IV E-V

3. A- V B-IV C-III D-II E-I

4. A- I B-V C-IV D-II E-III

Correct Option: A
Explanation:

Electrical unit     Single unit

(I) ampere-second                   coulomb

(II) volt-ampere                         Ampere

(III) volt-ampere$^{-1}$         Volt

(IV) walt/ampere ohm              Ohm

(V) joule / ampere second       Volt

So correct options are A- I B-III C-IV D-II E-V

Hence option A is correct.

The units of fundamental physical quantities are called

1. Fundamental units

2. Derived units

3. Both a and b

4. None of the above

Correct Option: A
Explanation:

The units of fundamental physical quantities are called fundamental units. They are length, mass and time.
Hence option A is correct.

Units of physical quantities can be expressed in terms of fundamental units and such units are called:

1. Fundamental units

2. Derived units

3. Both a and b

4. None of the above

Correct Option: B
Explanation:

Units of physical quantities can be expressed in terms of fundamental units and such units are called $\text{derived units}$.

Unit of area can be an example for derived unit. If $L$ is the length of the square then $L \times L$ is $L^{2}$ is its area. Hence, option A is correct.

Which of the following relationships are wrong?

1. $1 \,atm\approx 0.1 \, bar$

2. $1 \,liter= 1 \, dm^3$

3. $1\, J =0.239 \, cal$

4. $1\, eV =9.11 \times 10^{-4} J$

Correct Option: A,D
Explanation:

$1\quad atm=1.01325\quad bar\approx 1\quad bar\neq 0.1\quad bar$

$1\quad litre={ 10 }^{ -3 }{ m }^{ 3 }=1{ dm }^{ 3 }$
$1\quad cal =4.18\quad J \Rightarrow 1\quad J =0.239\quad cal\ 1\quad ev=1.6\times { 10 }^{ -19 }J \neq 9.11\times { 10 }^{ -4 }J$
Therefore, $(A). (D)$ are the correct answer.

One gram of mass is equal to:

1. $5\times { 10 }^{ 10 }erg$

2. $9\times { 10 }^{ 20 }erg$

3. $7\times { 10 }^{ 5 }erg$

4. $11\times { 10 }^{ 12 }erg$

Correct Option: B
Explanation:

$E=mc^2$

$E=1\ g \times (3\times 10^{10}\ cm/s)^2$
$=9\times 10^{20}\ erg$

Which of the following are incorrect SI units?

1. Amount of substance in mol L$^{-1}$

2. Pressure of gas in pascal

3. Density of a solid in kg m$^{-3}$

4. Force in newton

Correct Option: A
Explanation:

The SI units is based on seven base units. These are metre, kilogram, second, ampere, kelvin, mole and candela.

Here Pascal is SI unit of pressure
Newton is unit of force

Amount of substance has a SI unit $mol/ m^3$
Option A is the incorrect SI Unit.

Kelvin scale has:

1. no fixed points

2. one fixed point.

3. two fixed points

4. none of these

Correct Option: C
Explanation:

In Kelvin scale, temperature is expressed in Kelvin. In SI system, Kelvin is the unit of temperature. In this scale of temperature, zero of the scale corresponds to $-273^0C$, which is said to be the temperature at which the volume of a gas reduces to zero. Hence, $-273^0C$ is also known as the absolute zero. For the same reason, this scale of temperature is also known as absolute scale of temperature. On this scale, the lower fixed point i.e. the temperature of melting ice at normal pressure is +273K and the upper fixed point i.e. the temperature of boiling water at normal pressure is 373K.

What temperature scale must always be used when working gas law problems?

1. Celsius Scale

2. Kelvin Scale

3. Rankine Scale

4. Fahrenheit scale

Correct Option: B
Explanation:
You should always use the Kelvin scale to measure temperatures of gases for use with the gas laws.
Imagine you have a gas at 1$^0C$ and it is heated to $2^0C$. Just using Celsius temperatures you have doubled the temperature when in reality the amount of additional kinetic energy of a gas at $2^0C$ is only slightly higher than a gas at $1^0C.$
Also, imagine working a problem where you would need to divide by a temperature of $0^0C$. Wouldn't work! You have the same issue at $0K$, but since the material would not be a gas at $0K$ it is not an issue.
So we use kelvin scale always in gas problems.Option B is correct.

Which temperature scale is the primary unit of measurement and analysis in the physical world?

1. Celsius Scale

2. Kelvin Scale

3. Fahrenheit Scale

4. None of these

Correct Option: B
Explanation:
The kelvin is a unit of measure for temperature based upon an absolute scale. It is one of the seven base units in the International System of Units (SI) and is assigned the unit symbol K.
The Kelvin scale is an absolute, thermodynamic temperature scale using as its null point absolute zero, the temperature at which all thermal motion ceases in the classical description of thermodynamics.

The boiling point of water on the Kelvin scale is:

1. $373.15 K$

2. $273.15 K$

3. $373 K$

4. $374.15 K$

Correct Option: A
Explanation:
The boiling point of a substance is the temperature at which the liquid changes into a vapor.
Boiling point of water is $100^0C$

To convert kelvin scale, we have to add 273.15 to $^0C$ scale value
So,
$100^0C=100+273.15=373.15K$

Hence, option $A$ is correct.

Mathematical relation for conversion of Temperature from Celsius scale to Fahrenheit scale is:

1. $F = \frac{ 5 }{ 9} C + 32$

2. $C = \frac{ 9 }{ 5 }F + 32$

3. $F =\frac{ 9 }{ 5 }C + 32$

4. $F =\frac{ 9 }{ 5 }C - 32$

Correct Option: C
Explanation:
$T _C =(T _F - 32) \frac { 5 }{ 9 }$
${ T } _{ F }=(\frac { 9 }{ 5 } \times { T } _{ C })+32$
$T _C=$Temperature in celsius scale.
$T _F=$Temperature in Fahrenheit scale.
Option C is correct.

Select the correct statement(s):

1. The celsius scale is the fundamental unit of the temperature scale.

2. Kelvin scale defined as $273.16$ of the triple point (equilibrium among the solid, liquid, and gaseous phases) of pure water.

3. It is defined as $\frac{ 1 }{ 273.16}$ of the triple point (equilibrium among the solid, liquid, and gaseous phases) of pure water.

4. None of these

Correct Option: C
Explanation:

Options A and B are incorrect. The Kelvin scale is the fundamental unit of the Temperature scale. It is defined as $\frac{ 1 }{ 273.16 }$ of the triple point (equilibrium among the solid, liquid, and gaseous phases) of pure water. Hence, option C is correct.

A solution of hydrochloric acid is required for an experiment. The experimenter must first prepare the solution for use by diluting $10.0 mL$ of the hydrochloric acid to create $200 mL$ of the solution.
Which of the following would be the poorest choice of glassware for measuring the solute for the dilution?

3. A burrette

4. A volumetric pipette

Correct Option: A
Explanation:
$\text{Option A is correct.}$
$\text{A graduated cylinder,measuring cylinder or mixing cylinder is a common piece of laboratory equipment }$$\text{used to measure the volume of a liquid} Thermometer that can measure rapidly changing temperature is: 1. Mercury-in-glass thermometer 2. Alcohol-in-glass thermometer 3. Platinum resistance thermometer 4. Thermocouple thermometer Correct Option: D Explanation: Thermometer that can measure rapidly changing temperature is thermocouple thermometer. Advantages of a thermocouple thermometer: (a) Easy to read by using a pointer or a digital display. (b) Wide range of temperature - 200^oC to 1600^oC (c) It has has a small thermal capacity and is used to measure rapidly changing temperatures. Centigrade or Celsius scale can be converted into Kelvin scale by which of the following formula? 1. ^oC = Temperature in Kelvin + 273.15 2. ^oC = Temperature in Kelvin - 273.15 3. ^oC = Temperature in Fahrenheit + 273 4. ^oC = Temperature in Fahrenheit - 273 Correct Option: B Explanation: Zero on the Celsius scale (0^0C) is now defined as the equivalent to 273.15K, with a temperature difference of 1\ ^o C equivalent to a difference of 1\ K, meaning the unit size in each scale is the same. T _c=T _k-273.15 T _k=Temperature in kelvin. T _c=Temperature in celsius. So, the correct option is B 1 atm equals to: 1. 1 torr 2. 76 torr 3. 760 torr 4. 100 torr Correct Option: C Explanation: To convert an atmosphere measurement to a torr measurement, multiply the pressure by the conversion ratio. One atmosphere is equal to 760 torr, so use this simple formula to convert: torr = atmospheres \times 760 The pressure in torr is equal to the atmospheres multiplied by 760. Hence, the correct option is C What is the correct unit for the following solution? 0.5mg of arsenic dissolved in 1kg of solution. (All the symbols given are in their standard form) 1. w/w 2. m 3. M 4. v/v 5. ppm Correct Option: A Explanation: 0.5 mg of arsenic dissolved in 1 kg of solution. Both of the solute and solvent are given in terms of mass. Therefore, Option a is correct. Which of the following can be expressed as grams per milliliter? 1. Boiling point 2. Rate of reaction 3. Molecular mass 4. Molarity 5. Density Correct Option: E Explanation: Boiling point is expressed in kelvin, molecular mass in kilograms, molarity in moles per litre, rate of reaction in moles per litre per second and density in grams per litre or milliltre. Convert 3,200\mu g to grams. 1. 3.2g 2. 0.0032g 3. 3,200,000g 4. 3,200,000,000g 5. 0.0000032g Correct Option: B Explanation: Solution:- As we know that, 1 \mu g = {10}^{-6} g \therefore \; 3200 \mu g = \left( 3200 \times {10}^{-6} \right) g = 0.0032 g 10^{3} stands for : 1. milli- 2. kilo- 3. centi- 4. micro- 5. nano- Correct Option: B Explanation: Name and Factor : milli- \displaystyle 10^{-3} kilo- \displaystyle 10^{3} centi- \displaystyle 10^{-2} micro- \displaystyle 10^{-6} nano- \displaystyle 10^{-9} Hence, the correct option is B. Statement 1: -273^0C is also known as absolute zero. Statement 2: ^0C = K + 273 . 1. Statement 1 and Statement 2 are correct and Statement 2 is the correct explanation of Statement 1. 2. Both the Statement 1 and Statement 2 are correct and Statement 2 is not the correct explanation of Statement 1. 3. Statement 1 is correct but Statement 2 is not correct. 4. Statement 1 is not correct but Statement 2 is correct. 5. Both the Statement 1 and Statement 2 are not correct. Correct Option: C Explanation: Absolute zero, temperature at which a thermodynamic system has the lowest energy. It corresponds to −273^oC ( 0 K). Celsius scale is 273 greater in value than Kelvin scale. ^0C = K - 273 10^{-6} stands for : 1. milli- 2. kilo- 3. centi- 4. micro- 5. nano- Correct Option: D Explanation: milli- \displaystyle 10^{-3} kilo- \displaystyle 10^{3} centi- \displaystyle 10^{-2} micro- \displaystyle 10^{-6} nano- \displaystyle 10^{-9} SI Unit for mass is : 1. Newton 2. Ounces 3. Stones 4. Kilogram Correct Option: D Explanation: SI unit of mass is Kilogram which is in MKS system. 10^{-9} cm is equal to : 1. 1 milli- cm 2. 1 kilo- cm 3. 1 centi- cm 4. 1 micro- cm 5. 1 nano- m Correct Option: E The base unit for the length in metric system is : 1. cm 2. m 3. in 4. yd Correct Option: B Explanation: Metre (m) is the basic unit of length in metric system. Temperature of hot red iron is 58^{\circ} F. If the temperature increases by 20^{\circ} F, what is its temperature now in kelvin? 1. 298.5 2. 300 3. 273 4. -80 Correct Option: A Explanation: Temperature after heating = 58 + 20 = 78^0F Temperature in Kelvin = (F - 32) \div 1.8 + 273 = (78-32) \div 1.8 +273 = 46 \div 1.8 + 273 = 25.55 + 273 = 298.5 K In the metric system, the prefix kilo-means : 1. 10^0 2. 10^{-1} 3. 10^{-2} 4. 10^2 5. 10^3 Correct Option: E Explanation: In the metric system, the prefix kilo-means \displaystyle 10^3. For example, 1 kg is equal to \displaystyle 10^3 g. 1 km is equal to \displaystyle 10^3 m. What is the temperature of water in kelvin if the water is at 44^{\circ}C ? 1. 330 2. 317 3. 229 4. 230 Correct Option: B Explanation: Temperature in K = Temperature in ^{\circ}C + 273 = 44^{\circ}C + 273 = 317 K. So, the correct option is B Convert -679^{\circ} F to celsius. 1. 412.24 2. -395 3. 963 4. -400 Correct Option: B Explanation: We know, \boxed { { }^{ 0 }C=\left( { }^{ 0 }F-32 \right) \times \frac { 5 }{ 9 } } \swarrow \searrow temp in { }^{ 0 }C temp in F. { }^{ 0 }C=\left( -679-32 \right) \times \dfrac { 5 }{ 9 } { }^{ 0 }C=-395 \therefore temperature in { }^{ 0 }C u -{ 395 }^{ 0 }C. Convert 30^oC to Kelvin scale. 1. 323K 2. 313 K 3. 303 K 4. 293 K Correct Option: C Explanation: To convert from Celsius scale to Kelvin scale, we add 273 to Celsius scale. So, 30 + 273 = 303\ K The centigrade (^0 C) scale can be converted into Kelvin scale by the formula: 1. Temperature in Kelvin + 273 2. Temperature in Kelvin - 273 3. Temperature in Fahrenheit + 273 4. Temperature in Fahrenheit - 273 Correct Option: B Explanation: The temperature T in Kelvin (K) is equal to the temperature T in degrees Celsius \displaystyle \left( ^{ \circ }{ C } \right) + 273: \displaystyle { T } _{ \left( k \right) }={ T } _{ \left( ^{ \circ }{ C } \right) }+273.15 Therefore, temperature in \displaystyle ^{ \circ }{ C } = temperature in Kelvin +273. Hence, option B is correct. Convert 44 K into Celsius scale. 1. -233^oC 2. -229^oC 3. -212^oC 4. -239^oC Correct Option: B Explanation: To convert from Kelvin scale to Celsius scale, subtract 273 from Kelvin scale, so 44-273=-229^oC. Hence, option B is correct. What is the physical state of water at -20^{\circ}C? 1. Solid 2. Liquid 3. Gas 4. None of the above Correct Option: A Explanation: Water at -20^{\circ}C is ice so it is in solid state. It freezes at 0^{\circ}C. On Celsius scale, 0 Kelvin is equal to: 1. 273^0C 2. 0^oC 3. -273^oC 4. -373^oC Correct Option: C Explanation: To convert from Kelvin scale to Celsius scale, subtract 273 from Celsius scale. 0K=$$0-273=-273^oC$

The international standards of weight and measures are made of:

1. gold silver alloys

2. platinum - iridium alloys

3. copper - gold alloys

4. platinum - iron alloys

Correct Option: B
Explanation:
The addition of 10% iridium to the platinum greatly increases its hardness and so reduces wear.Hence the international standards of weight and measures are made up of platinum and iridium alloys.

Electron Volt is a unit of:

1. Potential difference

2. Energy

3. Charge

4. Velocity

Correct Option: B
Explanation:

The electron volt (symbol eV; also written electronvolt) is a unit of energy equal to approximately 1.602$\times$10$^{−19}$ joule (SI unit J).

By definition, it is the amount of energy gained by the charge of a single electron moved across an electric potential difference of one volt.

Hence, the correct option is $B$

Parsec is the unit of:

1. Speed

2. Time

3. Distance

4. None of the above

Correct Option: A,C

Weight of a body is:

1. constant

2. not constant

3. does not change from place to place

4. both A and C

Correct Option: B
Explanation:

Mass of a body is constant whereas weight of a body depends on the acceleration due to gravity at that point. Therefore, weight of body is not constant & varies from place to place.

If the temperature of a water bath is $104^{0}\ F$ then its value in degree Celsius scale will be?

1. $35^{0}C$

2. $45^{0}C$

3. $50^{0}C$

4. $40^{0}C$

Correct Option: D
Explanation:

Conversion from Fahrenheit to Celsius

$(T\ °F − 32) \times \dfrac{5}{9} = t\ °C$

Substituting it, we get,

$(104\ °F − 32) \times \dfrac{5}{9} = 40\ °C$

Hence, the correct option is $D$

$mol.kg^{-1}$ is the unit of :

1. Momentum

2. Velocity

3. Pressure

4. Molality

Correct Option: D

$1^oC$ rise in temperature is equal to a rise of

1. $1^oF$

2. $9/5^oF$

3. $5/9^oF$

4. $33^oF$

Correct Option: B

The prefix femto stands for :

1. $10^9$

2. $10^{-12}$

3. $10^{-15}$

4. $10^5$

Correct Option: C

$1^{\circ}C$ rise in temperature is equal to rise of:

1. ${ 1 }^{ 0 }F$

2. ${ 9/5 }^{ 0 }F$

3. ${ 5/9 }^{ 0 }F$

4. ${ 33 }^{ 0 }F$

Correct Option: B
Explanation:

Solution:- (B) $\cfrac{9}{5} ℉$

As we now that,
$F = \cfrac{9}{5} C + 32$
As the temperature is risen by $1 ℃$-
$C' = C + 1$
Therefore,
$F' = \cfrac{9}{5} \left( C + 1 \right) + 32$
$F' = \cfrac{9}{5}C + \cfrac{9}{5} + 32$
$\Rightarrow F' = \left( \cfrac{9}{5}C + 32 \right) + \cfrac{9}{5}$
$\Rightarrow F' = F + \cfrac{9}{5}$
Hence $1 ℃$ rise in temperature is equal to the rise in $\cfrac{9}{5} ℉$.

The prefix zepto stands for:

[Note : unit in m]

1. $10^9$

2. $10^{-12}$

3. $10^{-15}$

4. $10^ {-21}$

Correct Option: D
Explanation:

Zepto = $10^{-21}m$ .

Which of the following is the correct value of $R$ in $SI$ units?

1. $0.083$ $bar$ $dm^{3}K^{-1}mol^{-1}$

2. $1.98\ cal K^{-1}mol^{-1}$

3. $8.314\times 10^{7} erg K^{-1}mol^{-1}$

4. $8.314 J\ K^{-1}mol^{-1}$

Correct Option: D
Explanation:

$R$ is called as universal gas constant or molar gas constant.

$R=0.0821\quad L\quad atm\quad { mol }^{ -1 }{ k }^{ -1 }\ R=0.0831\quad { dm }^{ 3 }bar\quad { mol }^{ -1 }{ k }^{ -1 }\ R=8.314\quad J\quad { mol }^{ -1 }{ k }^{ -1 }\ R=8.314\times { 10 }^{ 7 }erg\quad { mol }^{ -1 }{ k }^{ -1 }\ R=1.98\quad Cal\quad { mol }^{ -1 }{ k }^{ -1 }$
The $S.I$ units of molar gas constant $(R)$ is $J\quad { mol }^{ -1 }{ k }^{ -1 }$.
$\therefore \quad R=8.314\quad J\quad { mol }^{ -1 }{ k }^{ -1 }$ is the correct answer.

Which of the following has the highest numeric value?

1. $100$ Tm

2. $1000$ Gm

3. $10^4$ mm

4. $10^6$ nm

Correct Option: A
Explanation:

$100\ Tm=100000\ Gm$

$1000\ Gm$
$10^4\ mm=1\times10^{-10}\ Gm$
$10^6\ nm=1\times10^{-12}\ Gm$

If $T _1$ and $T _2$ are two temperatures, which of the following expressions will yield the same value whether both temperatures are given in Celsius or Kelvin?

1. $T _1+T _2$

2. $T _1-T _2$

3. $T _1\times T _2$

4. $\dfrac{T _1}{T _2}$

Correct Option: B

Weight of diamonds are measured in________.

1. aunce

2. Kg

3. carats

4. pounds

Correct Option: C
Explanation:

One carat is equal to exactly $0.2$ grams.

The word 'carat' came from the "carob" seed, which was used by diamond traders as the original unit.

Atomic radius is expressed in the _______ units.

1. angstrom

2. cm

3. m

4. nm

Correct Option: A
Explanation:

Atomic radius is usually expressed in Angstrom units. It is because the size of atom is very small. It is equivalent to $1\times {10}^{-10}$metres.

Mark the conversion factor which is not correct.

1. 1 atm $= 1.01325 \times 10^5 \ Pa$

2. 1 metre $= 39.37\ inch$

3. 1 litre $= 10^{-3}\ m^3$

4. 1 inch $= 3.33\ cm$

Correct Option: D
Explanation:

A. 1 atm = $1.01325 \times 10^5\ Pa$

B. 1 metre = $39.37\ inches$
C. 1 litre = $10^{−3}\ m^3$
D. 1 inch = $2.54\ cm$
option D is correct

Which of the following is wrong?

1. 1 inch = 2.54 cm

2. 1 foot = 3.305 m

3. 1 mile = 1.609 km

4. 1 lb. = 453.59 gm

Correct Option: B
Explanation:

Answer is option $B$.

Since $1$ $foot=0.3048m$

Energy spent in kilowatt-hour $=\cfrac {volt \times...........\times......}{1000}$.

1. ampere, hour

2. ohm,min

3. ampere,min

4. joule,hour

Correct Option: A
Explanation:

Energy = Work done $(in\ Watt) = Power\times time = Voltage \times current \times time$

$Work\ done\ (in\ kilowatt) = \dfrac{(Voltage\times current\times time)}{ 1000}$

$Or\ work\ done\ (in\ kilowatt) = \dfrac{(Volt\times ampere\times hour)}{ 1000}$

The commercial unit of electrical energy is :
1. Watt

2. Kilo Watt hour

3. Watt/ hour

4. Ohm

Correct Option: B
Explanation:

The kilowatt-hour is commonly used as a billing unit for energy delivered to consumers by electric utilities.

Which of the following is not a basic physical quantity?

1. Length

2. Force

3. Time

4. Amount of substance

Correct Option: B
Explanation:

The physical property of a body, substance or phenomenon that can be quantified by measurement is defined as a physical quantity.

There are seven fundamental physical quantities viz. time, length, mass, amount of substance, luminous intensity, temperature, and electric current.
Here force is a derived unit.
Thus the correct answer is force.

The amount of heat energy released when a fuel burns completely is called calorific value.

1. True

2. False

3. Nither

4. Either

Correct Option: B
Explanation:
$\text{Calorific value= heat released per kg of fule}$

$\text{The amount of heat energy released when a one kilogram of fuel burns completely is called calorific value.}$

$298 K$ is what temperature in Fahrenheit?

1. $76.73F$

2. $80F$

3. $75F$

4. $27F$

Correct Option: A
Explanation:

${ T } _{ K }={ (T } _{ F }+459.67)\times \frac { 5 }{ 9 } \ \Rightarrow 298={ (T } _{ F }+459.67)\times \frac { 5 }{ 9 } \ \Rightarrow \frac { 298\times 9 }{ 5 } -459.67={ T } _{ F }\ \Rightarrow { T } _{ F }=536.4-459.67={ 76.73 }^{ 0 }F$

Which of the following is the correct unit for measuring nuclear radii?

1. Micron

2. Millimetre

3. Angstrom

4. Fermi

Correct Option: D
Explanation:

$\text{Nuclear radii are measured in Fermi ie. }$$10^{-15}$

SI unit of energy is:

1. $kg\, m^2 s^{-2}$

2. $kg\, m^{-1} s^{2}$

3. $kg\, m^2 s^{-1}$

4. $kg\, m^2 s^{2}$

Correct Option: A
Explanation:

The power required to do work by the application of force is energy.

Energy has same unit as that of work.
$\therefore$ S.I unit of Energy is $kgm^2 s^{-2}$

The prefix of $10^{18}$ is:

1. giga

2. exa

3. kilo

4. nano

5. mega

Correct Option: B
Explanation:

The prefix of ${ 10 }^{ 3 }=$ kilo

${ 10 }^{ 6 }=$ mega
${ 10 }^{ 9 }=$ giga
${ 10 }^{ 18 }=$ exa
Therefore, the prefix of ${ 10 }^{ 18 }$ is exa

Prefix giga means:

1. $10^{-9}$

2. $10^{9}$

3. $10^{6}$

4. $10^{-6}$

Correct Option: B
Explanation:

The prefix of ${ 10 }^{ -9 }=$ nano

${ 10 }^{ 9 }=$ giga
${ 10 }^{ 6 }=$ mega
${ 10 }^{ -6 }=$ micro
Therefore, $(B)$ is the correct answer.

298 K is approximately what temperature in degrees Celsius?

1. $25^oC$

2. $24^oC$

3. $29^oC$

4. $27^oC$

Correct Option: A
Explanation:

Zero on the Celsius scale $(0^0C)$ is now defined as the equivalent to $273.15K$, with a temperature difference of $1^0C$ equivalent to a difference of $1K$, meaning the unit size in each scale is the same.

$T _k=T _c+273.15$
$T _k=$Temperature in kelvin.

$T _c=$Temperature in celsius.
$T _c=298-273=25^0C$.Option A is correct.

Unit of J $pa^{-1}$ is equivalent to:

1. $m^3$

2. $cm^3$

3. $dm^3$

4. none of these

Correct Option: A
Explanation:

J/Pa =  Work/Pressure =  Nm/Nm-2 = m3

Convert $48.50mL$ to liters.

1. $0.4850L$

2. $4850L$

3. $0.04850L$

4. $0.00004850L$

5. $4.850L$

Correct Option: C
Explanation:

We know that the 1 mL is equals to 0.001 L

hence $48.50$ mL is equals to $48.50$ multiplied by $0.001$ which comes $0.04850$ L.

Name and unit are listed, which is NOT correctly written?

1. Torr and pressure

2. Mass and grams

3. Heat energy and kilopascals

4. Volume and milliliter

5. Temperature and Kelvin

Correct Option: C
Explanation:

Unit of Heat energy is joule ($J$) not kilopascals. kilopascal is unit for pressure.

Hence the correct option is C.

Which of the following is not a conversion factor?

1. 12 eggs = 1 dozen

2. 30 lbs.

3. 60 miles per hour

4. 1 km/1,000 m

5. 4 apples per week

Correct Option: C,D,E
Explanation:

Conversion factor involves same units. For example, length can be converted to length only, time to time only, etc.

SI unit for time is :

1. minutes

2. hours

3. seconds

4. days

Correct Option: C
Explanation:

SI unit of time is seconds.

Which temperature is hottest?

1. $17^oC$

2. $58^o F$

3. $290 K$

4. $16^o C$

Correct Option: A
Explanation:
Relation between celsius kelvin and fahrenheit scale.
${ T } _{ C }=\frac { 5 }{ 9 } ({ T } _{ F }-32){ =T } _{ K }-273.15$

$17^0C=17^0C$
$58^0F=\frac {58-32} {1.8}=14.44^0C$
$290K={290-273.15}^0C=16.85^0C$

$16^0C=16^0C$

$17^0C$ is hotter.
Option A is correct.

$10^{-12}$ is called :

1. Terra

2. Pico

3. Giga

4. Mega

Correct Option: B
Explanation:

$10^{-12}$ is called as pico.

Which is correct option about the prefix centi is:

1. One thousand

2. One thousandth

3. One hundred

4. One hundredth

5. One million

Correct Option: D
Explanation:

Selected Prefixes and Their Meanin

G  billions (U.S.)  giga
M  Million mega
k  thousand  kilo
h*  hundred  hecto*
da*  ten  deka*
d*  tenth  deci*
c*  hundredth  centi*
m*  thousandth  milli
$\mu$  millionth  micro
n  billionth (U.S.)  nano

What is the density of a metal which has a mass of $15g$ and a volume of $2mL$?

1. $7.5$

2. $17$

3. $0.15$

4. $13$

5. $30$

Correct Option: A
Explanation:

$Density= \cfrac {mass}{volume}= \cfrac {15g}{2ml}= 7.5\quad g/ml$

To convert Celsius scale to Kelvin scale:

1. add $273$ to Celsius scale

2. subtract $273$ from Celsius scale

3. multiply $273$ with Celsius scale

4. divide $273$ by Celsius scale

Correct Option: A
Explanation:

To convert from Celsius scale to Kelvin scale, add 273 to Celsius scale.

The S.I. unit of weight is:

1. kilogram

2. gram

3. newton

4. milligram

Correct Option: C
Explanation:

The S.I. unit of weight is newton since weight is the reaction force of an object due to gravity.

To convert Kelvin scale to Celsius scale:

1. add $273$ to Kelvin scale

2. subtract $273$ from Kelvin scale

3. multiply $273$ with Kelvin scale

4. divide $273$ by Kelvin scale

Correct Option: B
Explanation:
$^0C=K-273$
To convert Kelvin to Celsius, subtract $273$ from kelvin scale.

Hence, option $B$ is the answer.

What is the physical state of water at $125^{\circ} C$?

1. Solid

2. Liquid

3. Gas

4. None of the above

Correct Option: C
Explanation:

Water boils at $100^{\circ}C$ and it converts into vapour above this temperature.

Convert $100^oC$ to kelvin :

1. $273$

2. $373$

3. $473$

4. $573$

Correct Option: B
Explanation:

The formula for conversion of centigrade unit to kelvin is :

$T(K)= T(^oC) + 273$

$T(K)=100+273$

$=373K$

Option (B) is correct.

The atmospheric pressure at sea level is:

1. 1 atm

2. 10 atm

3. 100 atm

4. 1 pascal

Correct Option: A
Explanation:

The atmospheric pressure at sea level is 1 atm.

The S.I. unit of length is:

1. metre

2. kilometre

3. foot

4. yard

Correct Option: A
Explanation:

The S.I. unit of length is metre.

Convert $-273^oC$ to Kelvin scale.

1. 0 K

2. 273 K

3. 300 K

4. 5 K

Correct Option: A
Explanation:

To convert from the Celsius scale to the Kelvin scale, we add $273$ to the Celsius scale. So, $-273+273=0\ K$

Hence, the correct option is $A$

What is the physical state of water at $30^{\circ} C$?

1. Solid

2. Liquid

3. Gas

4. None of the above

Correct Option: B
Explanation:

Water at $30^{\circ}C$ is liquid and it remains in liquid state from $0^{\circ}C$ to $100^{\circ}C$.

The S.I. unit of temperature is:

1. kelvin

2. celsius

3. fahrenheit

4. None of the above

Correct Option: A
Explanation:

The SI unit of temperature is kelvin.

What is the S.I unit of volume?

1. cubic centimeter

2. cubic meter

3. cubic foot

4. cubic millimeter

Correct Option: B
Explanation:

The S.I unit of volume is cubic meter $(m^3)$.

Hence the correct option is B.

The SI unit for force is:

1. Torr

2. Newton

3. Joule

4. Dyne

Correct Option: B
Explanation:

Force is the product of mass and acceleration

$\therefore$ Force $=$ Mass $\times$ acceleration
The S.I unit of force is $kg.m/s^2$ or Newton
$1$ Newton $= 10^5$ Dyne

Option $B$ is the correct answer.

Our body temperature is maintained at :

1. ${20 ^ 0C }$

2. ${41 ^0 C}$

3. ${37 ^0 C}$

4. ${11^0 C}$

Correct Option: C
Explanation:

Our body temperature is maintained at $37^\circ C$ or $98^\circ F$ on an average. Our body has thermo-regulation mechanism that keeps the body at optimum operating temperature. Water plays an important role in this mechanism.

The S.I unit of mass is ___________.

1. kilogram

2. gram

3. decigram

4. milligram

Correct Option: A
Explanation:

The S.I unit of mass is kilogram (kg).

Hence the correct option is A.

The S.I. unit of pressure is:

1. pascal

2. atm

3. newton

4. None of the above

Correct Option: A
Explanation:

The SI unit of pressure is pascal. Newton is the unit of force and atm is not the S.I. unit of pressure.

One atmosphere is numerically equal to approximately:

1. ${ 10 }^{ 6 }\quad dyne\quad { cm }^{ -2 }$

2. ${ 10 }^{ 2 }\quad dyne\quad { cm }^{ -2 }$

3. ${ 10 }^{ 4 }\quad dyne\quad { cm }^{ -2 }$

4. ${ 10 }^{ 8 }\quad dyne\quad { cm }^{ -2 }$

Correct Option: A
Explanation:

$P _{dyne/cm^2}=P _{atm}\times 1.01325\times 10^6$

$P _{atm}=1$

then $P _{dyne cm^2}=1.01325\times 10^6$

Option A is Correct.

SI unit of temperature is ________ .

1. $K$

2. $^oC$

3. $^oF$

4. u

Correct Option: A
Explanation:

SI unit of temperature is Kelvin because Kelvin was the the first person to suggest using Kelvin in thermodynamic temperature scale.

A volume of ${ 1m }^{ 3 }$ is equal to ?

1. ${ 1000\quad cm }^{ 3 }$

2. ${ 100\quad cm }^{ 3 }$

3. ${ 10\quad dm }^{ 3 }$

4. ${ 10 }^{ 6 }{ cm }^{ 3 }$

Correct Option: D

The greatest of the combination is?

1. $(9.0\pm 0.3)$ S.I unit

2. $(9.0\pm 0.2)$ S.I unit

3. $(9.0\pm 0.1)$ S.I unit

4. $(9.0\pm 0.5)$ S.I unit

Correct Option: D

S.I unit for the coefficient of viscosity is equal to?

1. $Nm^{-1}s$

2. $Pa s^{-1}$

3. $Nm^{-2} s$

4. $Pa s^{-2}$

Correct Option: C

The temperature of absolute zero is _______

1. $273.15^{0}C$

2.  $0^{0}C$

3. $-373^{0}C$

4. $-273.15^{0}C$

Correct Option: D
Explanation:

The temperature of absolute zero is $T=t+273.15$

Absolute Zero$=T=0$

Then $0=t+273.15 ^0C$

$t=-273.15 ^oC$

One fermi is?

1. $10^{-15}$ cm

2. $10^{-13}$ cm

3. $10^{-10}$ cm

4. $10^{-12}$ cm

Correct Option: B
Explanation:

One fermi = $10^{-15}m = 10^{-13}cm$ .

Which one of the following temperatures is approximately equal to "room temperature ?"

1. $0\ K$

2. $293\ K$

3. $100$ Degree Celsius

4. $0$ Degree Celsius

Correct Option: B

The symbol of S.I unit of amount of substance is:

1. mole

2. density

3. equivalent weight

4. molecular weight

Correct Option: A
Explanation:

Mole is used to represent the amount of a substance. For an element or a compound, mole is given by

$n=\dfrac{Weight\ in\ grams}{Molecular\ Weight}$

Its SI unit is $mole$.

Unit of luminous intensity is:

1. mole

2. candela

3. kelvin

4. ampere

Correct Option: B
Explanation:

Luminous intensity is a measure of the wavelength-weighted power emitted by a light source in a particular direction per unit solid angle.

Based on the luminosity function, a standardized model of the sensitivity of the human eye.
The SI unit of luminous intensity is candela(cd).

So, option ( B ) is correct.

What is the SI unit of mass?

1. kg

2. LBS

3. Pounds

4. None of these

Correct Option: A
Explanation:

• SI unit definition is a unit of measurement that is a universally accepted system used for scientific and technical work all over the world.
• The kilogram is the SI base unit of mass and is equal to the mass of the international prototype of the kilogram, a platinum-iridium standard that is kept at the International Bureau of Weights and Measures (BIPM).

The S.I unit of atmospheric pressure is :

1. $L\ atm$

2. $N/m$

3. $Pascal$

4. None of these

Correct Option: C
Explanation:

The S.I unit of atmospheric pressure is $N/m^2$ or $Pascal$.

$1\quad Pascal =1N/m^2$
$1\quad atm =101325\quad Pascal$
$1\quad bar =10^5\quad Pascal$

The standard temperature is:

1. $273^0C$

2. $273K$

3. $-273K$

4. $23K$

Correct Option: B
Explanation:

The standard temperature is considered to be $273K$

i.e. $0°C$

Among the following, the highest value of prefix is:

1. yocto

2. deca

3. giga

4. yotta

Correct Option: D
Explanation:

Yocto= $10^{-24}$,             Deca= $10^1$

Griga=$10^9$,                    Yotta=$10^{24}$

Therefore, the highest value of prefix is Yotta  $10^{24}$

The correct option is (D)

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