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Guiding rules for tabulation - class-XI

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Let m be the mid-point be the upper class limit of a continuous frequency distribution The lower class limit of the class is

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A
$2m-L$
💡 Explanation:

Mid point=$\dfrac{upper  limit+ lower  limit}{2}$

$\Rightarrow m=\dfrac{L+lower  limit}{2}$
$\Rightarrow Lower   limit=2m-L$

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