Sum to infinite terms of a gp - class-XI

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Question 1 of 67

The value of $3 - 1 + \frac{1}{3} - \frac{1}{9} + \ldots $ is equal to

Select Your Answer:

$\dfrac{{20}}{9}$

$\dfrac{{9}}{20}$

$\dfrac{{9}}{4}$

$\dfrac{{4}}{9}$

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