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Interquartile range - class-XII
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The median of a symmetrical distribution, whose lower and upper quartiles are 60 and 80 respectively, is
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A
70
💡 Explanation:
Given, lower quartile $=60$ and upper quartile $=80$
$\therefore$ median $=\frac{\mbox{
lower quartile
}+\mbox{
upper quartile
}}{2}=\dfrac{60+80}{2}=70$