Magnetometry and Earth's Magnetic Field - Class XI
Questions on deflection magnetometers, vibration magnetometers, bar magnets, magnetic moments, oscillations, and earth's magnetic field components
Questions
In both $\tan A$ and $\tan B$ positions in a Deflection Magnetometer, the bar magnet is always placed
- parallel to the magnetic needle of the deflection magnetometer
- parallel to the aluminum pointer of the deflection magnetometer
- perpendicular to the aluminum pointer
- parallel to the arm having the wooden scale
The restoring couple for a magnet oscillating in the vibration magnetometer is provided by
- horizontal component of earths magnetic field
- gravity
- torsion in the suspended thread
- magnetic field of magnet
- Both A and R are true and R is the correct explanation of A
- Both A and R are true and R is not correct explanation of A
- A is true, But R is false
- A is false, But R is true
Deflection magnetometer is held in $\tan B$ position. A magnet placed on one of its arms produces no deflection. This implies that the axis of the magnet is
- in the east - west direction
- in the north-south direction
- perpendicular to the wooden bench
- North - East
The magnets of same magnetic moment $M$ and different lengths are placed in $tan; A$ position. The fields at equal distances from them are :
- greater for long magnet
- greater for small magnet
- equal for both
- zero
A D.M.M is in tan A position in a region where $B _H$ is 50$\mu $T. When a magnet is placed at a suitable distance the deflection obtained is 45$^{0}$. The resultant magnetic field at the centre of the compass is
- 50$\mu $T
- $50\sqrt{2}\mu \top $
- 25 $\mu $ T
- 100$\mu $ T
To measure the magnetic moment of a bar magnet, one may use.
- a tangent galvanometer.
- a deflection galvanometer if the earth's horizontal field is known.
- an oscillation magnetometer if the earth's horizontal field is known.
- both deflection and oscillation magnetometer if the earth's horizontal field is not known.
When two magnets are placed $20\ \text{cms}$ and $15\ \text{cms}$ away on the two arms of a deflection magnetometer, it shows no deflection. The ration of magnetic moments is :
- $\displaystyle\dfrac{M _1}{M _2}=\dfrac{64}{27}$
- $\displaystyle\dfrac{M _1}{M _2}=\dfrac{4}{3}$
- $\displaystyle\dfrac{M _1}{M _2}=\dfrac{16}{9}$
- $\text{none of these}$
The factor on which the period of oscillation of a bar magnet in uniform magnetic field depends is
- nature of suspension fibre
- length of the suspension fibre
- vertical component of earths magnetic induction
- moment of inertia of the magnet
When a D.M. is set in $\tan A$ position, the deflection is $30^{o}$ for a magnet A placed at a distance of $40\ cm$ from the midpoint of the D.M. When the D.M. is kept in $\tan B$ position another magnet B produces a deflection of $60^{o}$, when placed at the same distance. The ratio of the magnetic moments of A and B is :
- $1 : 2$
- $1 : 3$
- $2 : 3$
- $1 : 6$
Two magnets when placed in $\tan A$ position at the same distance cause deflections of $30^{o}$ and $60^{o}$. The ratio of their magnetic moments is :
- $3 : 1$
- $1 : 3$
- $1 : 2$
- $2 : 1$
Vibration magnetometer works on the principle of
- torque acting on the bar magnet and rotational inertia
- force acting on the bar magnet and rotational inertia
- both the force and torque acting on the bar magnet
- neither force nor torque
A short magnet when placed at a distance of $15 cm$ in $\tan A$ position produces a deflection of $60^{o}$. If the magnet is cut into $3$ equal parts and one of them is kept at the same distance in $\tan A$ position, the deflection is :
- $20^{o}$
- $30^{o}$
- $45^{o}$
- $60^{o}$
Two bar magnets of same size with magnetic moments M$ _{1}$ and M$ _{2}$ (M$ _{1}$ > M$ _{2}$ ) are simultaneously used at the tan A position in a DMM. When the magnets are placed with unlike poles in contact the deflection is 30$^{0}$ and when like poles are in contact the deflection is 60$^{0}$ . Then $\dfrac{M _{1}}{M _{2}} :$
- $\dfrac{3}{1}$
- $\dfrac{3}{4}$
- $\dfrac{6}{1}$
- $\dfrac{2}{1}$
Two bar magnets A and B are placed on the two arms of a deflection magnetometer. When their distances from the centre of the needle are 20 cm and 40 cm respectively, the needle lies in the magnetic meridian. If the moment of the magnet A is 100 Am$^{2}$, then the moment of the magnet B is:
- 400 Am$^{2}$
- 800 Am$^{2}$
- 1200 Am$^{2}$
- 1600 Am$^{2}$
When a short bar magnet is kept at a distance of 20 cm from the centre of D.M., in Tan A position, the deflection is 45$^{0}$ . If $H=30$ A/m, the moment of the magnet is :
- 1.5 $\times $ 10$^{-2}$ Am$^{2}$
- 1.51Am$^{2}$
- 3.01Am$^{2}$
- 1.31Am$^{2}$
A short bar magnet is kept at a distance of 30 cm from the centre of the compass box on D.M, which is in Tan A position. The deflection is 45$^{0}$. If the horizontal component of earth's field strength is 30 A/m, the magnetic moment of the magnet is
- $0.128\pi Am^{2}$
- $1.28\pi Am^{2}$
- $128\pi Am^{2}$
- $12.8\pi Am^{2}$
The tangent of deflection of angle of the needle of a DMM, taken along the y-axis is plotted against the distance d between the needle and a short magnet. The slope of the curve varies as
- d
- d$^{-1}$
- d$^{2}$
- d$^{-3}$
The ratio of magnetic moments of two bar magnets is $5 : 2$. If the deflection produced by the first magnet in the D.M. in $\tan A$ position is $60^{o}$ , the deflection due to the second magnet kept at the same distance in tan A position is :
- greater than $45^{o}$
- less than $45^{o}$
- less than $30^{o}$
- greater than $90^{o}$
A deflection magnetometer is in Tan A position in a region where the Earth's horizontal component of magnetic induction is $60\times 10^{-6}T$. When a magnet is placed at a suitable distance, a deflection of $45^{0}$ is obtained. The induction field strength of the magnet is :
- $60\times 10^{-5}T $
- $6\times 10^{-5}T $
- $0.6\times 10^{-5}T $
- $6\times 10^{-6}T $
Two short magnets are kept on opposite arms of the DMM at 12 cm and 16 cm. If there is no deflection in the needle, the ratio of the magnetic moments is :
- 3 : 4
- 4 : 3
- 9 : 14
- 27 : 64
A DMM is arranged at the magnetic pole of earth in $\tan A$ position. If a bar magnet is placed at some distance from the needle, deflection is
- $0^{o}$
- $90^o$
- $45^{o}$
- $180^{o}$
A short bar magnet with its $N -$ pole pointing north produces a null point at a distance $15 cm$ from its midpoint. If this magnet is used in $\tan A$ position of deflection magnetometer at a distance $15 cm$ from the magnetic needle, the deflection is
- $\tan^{-1}( 3/2)$
- $\tan^{-1}( 3/4)$
- $\tan^{-1}( 2)$
- $\tan^{-1}( 1/2)$
The ratio of the magnetic moment of two short magnets when they give zero deflection in $\tan B$ position when placed at $12 cm$ and $18 cm$ from centre of a deflection magnetometer is :
- $\dfrac{8}{27}$
- $\dfrac{27}{8}$
- $\dfrac{9}{7}$
- $\dfrac{4}{9}$
Two bar magnets are placed together in a vibration magnetometer vibrates with a time period is $3s$ . If one magnet is reversed, the combination takes $4s$ for one vibration. The ratio of their magnetic moments is :
- $3 : 1$
- $5 : 18$
- $18 : 5$
- $25 : 7$
Two small magnets of moments $M$ and $8M$ produce no deflection in $\tan A$ position when $M$ is at a distance $8 cm$. The distance of the magnet of moment $8M$ is
- $16 cm$
- $24 cm$
- $12 cm$
- $18 cm$
A DMM is placed with its arms in $N-S$ direction.The distance at which a short bar magnet having $\dfrac {M}{B _{H}}=80Am^{2}/T$ should be placed, so that the needle can stay in any position is (nearly)
- $2.5 cm$ from the needle, $N-$pole pointing GS
- $2 cm$ from the needle, $N -$ pole pointing GN
- $4 cm$ from the needle, $N -$ pole pointing GN
- $2 cm$ from the needle, $N -$ pole pointing GS
A short magnet produces a deflection of $30^{o}$ when placed at some distance in $\tan A$ position of the magnetometer. If another magnet of same length and double the pole strength is kept at the same distance in $\tan B$ position, the deflection produced is
- $30^{o}$
- $60^{o}$
- $45^{o}$
- $0^{o}$
Two magnets of a magnetic moments $M$ and $2M$ are placed in a vibration magnetometer, with the identical poles in same direction. The time period of vibration is ${T} _{1}$. If the magnets are placed with opposite pole together and vibrate with time period ${T} _{2}$ then :
- ${T} _{2}$ is infinite
- ${T} _{2}={T} _{1}$
- ${T} _{2}>{T} _{1}$
- ${T} _{2}<{T} _{1}$
A magnetic needle of pole strength $20\sqrt{3}$ Am is pivoted at its centre.Its N -pole is pulled eastward by a string.The horizontal force required to produce a deflection of $30^o$ from magnetic meridian (taken $B _H=10^{-4}T$) is :
- $4\times 10^{-3}N$
- $2\times 10^{-3}N$
- $\dfrac{2}{\sqrt{3}}\times 10^{-3}N$
- $4\sqrt{3}\times 10^{-3}N$
A short magnet with its N-pole pointing towards north produces a null point at a distance 15 cm from its mid-point. If this magnet is used in tan A position of deflection magnetometer at a distance 15 cm from the magnetic needle, what will be the deflection
- $tan^{-1}(\frac{1}{2})$
- $tan^{-1}(\frac{3}{2})$
- $tan^{-1}(\frac{3}{4})$
- $tan^{-1} (2)$
A compass needle placed at a distance r from a short magnet in tan A position shows a deflection of $60^0$. If the distance is increased to $r(3)^{1/3}$, then the deflection of the compass needle is:
- $30^0$
- $60^0 \times (3)^{1/3}$
- $60^0 \times (3)^{2/3}$
- $60^0 \times (3)^{3/3}$
The time period of a thin magnet is 4 s. If it is divided into two equal halves, then the time period of each part will be:
- 4s
- 1s
- 2s
- 8s
The length of a magnet is very large as compared to its width and breadth. The time period of its oscillation in a vibration magnetometer is $2$ s. The magnetic is cut perpendicular to its length into three equal parts and three parts are then placed on each other with their like poles together. The time period of this combination will be
- $2 s$
- $\frac{2}{3} s$
- $\sqrt 3 s$
- $\frac{2}{\sqrt3} s$
A magnet makes 12 oscillation per minute at a place where horizontal component of earth's field is $6.4 \times 10^{-3}$ T. It is found to require 8 seconds per oscillation at another place X. The vertical component of earths field at X where resultant field makes angle $60^0$ with horizontal is $ ---- \times 10^{-4}$ T
- $\frac{25}{\sqrt{3}}$
- $\sqrt{3}$
- $25\sqrt{3}$
- 25
A vibration magnetometer placed in magnetic meridian has a small bar magnet. The magnet executes oscillations with a time period of 2 s in earths horizontal magnetic field of 24 microtesla. When a horizontal field of 18 microtesla is produced opposite to the earths field by placing a current carrying wire, the new time period of magnet will be:
- (a) 4 s
- (b) 1 s
- (c) 2s
- (d) 3 s
An axle or truck is $2.5$ m long.If the truck is moving due North at ${ ms }^{ -1 }$ at a place where the vertical component of the earth's magnetic field is 90 $\mu T$, the potential difference between the two ends of the axle is
- 6.75 mV with West end positive
- 6.75 mV with East end positive
- 6.75 mV with North end positive
- 6.75 mV with South end positive
A deflection magnetometer is adjusted in the usual way. When a magnet is introduced, the deflection observed is, and the period of oscillation of the needle in the magnetometer is $T$. When the magnet is removed the period of oscillation is $T _{o}$. The reaction between $T$ and $T _{o}$ is :
- $T^{2}={T} _{o}^{2}cos\theta$
- $T=T _{o}cos\theta$
- $T=\cfrac{T _{o}}{cos\theta}$
- $T^{o}=\cfrac{{T} _{o}^{2}}{cos\theta}$
A combination of two bar magnets, in vibration magnetometer, makes $10$ oscillations per second if their like poles are tied together and $2$ oscillations per second when unlike poles are tied together. If induced magnetism is neglected, then the ratio of their magnetic moments is
- $\displaystyle \frac{3}{2}$
- $\displaystyle \frac{13}{12}$
- $\displaystyle \frac{8}{9}$
- $\displaystyle \frac{12}{11}$
When two magnets are placed $15\ cms$ and $20\ cms$ away from a deflection magnetometer on two arms, no deflection is observed. The ratio of magnetic dipole moments is
- $\displaystyle\dfrac{3}{4}$
- $\displaystyle\dfrac{9}{16}$
- $\displaystyle\dfrac{27}{64}$
- $\displaystyle\dfrac{81}{256}$
A vibration magnetometer placed in magnetic merlian has a small bar magnet. The magnet executes oscillations with a time period of $2 ,s$ in earth's horizontal magnetic field of $24 ,mu T$. When a horizontal field of $18 ,mu T$ is produced opposite to the earth's field by placing a current carrying wire, the new time period of the magnet will be then
- $1 ,s$
- $2 ,s$
- $3 ,s$
- $4 ,s$
When two short magnets having magnetic moments in the ratio $125 : 216$ are placed on the opposite arms of the Deflection Magnetometer, there is no deflection recorded. The distance between the centres of the magnets is $22 cm$. The distance of the weaker magnet from the center of D.M is :
- $11 cm$
- $16 cm$
- $18 cm$
- $10 cm$
In deflection magnetometer, to find dipole moment $M$ of a magnet, angle of deflection should be
- $0^0$
- $90^0$
- $45^0$
- any angle
Two bar magnets are placed in a Vibration Magnetometer and allowed to vibrate. They make $20$ oscillations per minute when their similar poles are on the same side and they make $15$ oscillations per minute with their opposite poles lie on the same side. The ratio of their moments is :
- $9:5$
- $25:7$
- $16:9$
- $5:4$
A small magnet of dipole moment $M$ is kept on the arm of a deflection magnetometer set in $\tan A$ position at a distance of $0.2\ m$. If the deflection is $60^o$, the value of $P$ is : ($ B _H=0.4\times 10^{-4}\ T$)
- $2.77\ Am^2$
- $8\ Am^2$
- $0.2\ Am^2$
- $none\ of\ these$
In end on and broadside on position of a deflection magnetometer, if ${\theta} _{1}$ and ${\theta} _{2}$ are the deflections produced by short magnets at equal distances, then $\tan { { \theta } _{ 1 } } /\tan{{ \theta } _{ 2 }}$ is
- $2:1$
- $1:2$
- $1:1$
- None of these
The length of a bar magnet is large compared to its width and breadth. The time period of its oscillation in a vibration magnetometer is $2 s$. The magnet is cut along its length into three equal parts and three parts are then placed on each other with their like poles together. The time period of this combination will be :
- $2\ s$
- ${2}/{3}\ s$
- $2\sqrt{3}\ s$
- ${2}/{\sqrt{3}}\ s$
To measure the magnetic moment of a bar magnet, one may use
- a deflection galvanometer if the earth's horizontal field is known
- an oscillation magnetometer if the earth's horizontal field is known
- both deflection and oscillation magnetometer if the earth's horizontal field is not known
- all of the above
Two short magnets have equal pole strengths but one is twice as long as the other. The shorter magnet is placed $20\ cm$ in $\tan A$ position from the compass needle. The longer magnet must be placed on the other side of the magnetometer for no deflection at a distance equal to
- $20\ cm$
- $20\times (2)^{1/3} cm$
- $20\times (2)^{2/3} cm$
- $20\times (2)^{3/3} cm$
With a standard rectangular bar magnet 'the time period of a vibration magnetometer is $4 s$. The bar magnet is cut parallel to its length into four equal pieces. The time period of vibration magnetometer when one piece is used (in second) (bar magnet breadth is, small) is
- $16$
- $8$
- $4$
- $2$