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Errors and approximations - class-XII

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The approximate value of $\sqrt[10]{0.999}$ is 

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A
0.9999
💡 Explanation:

Using binomial approximation, (1 - x)^(1/n) is approximately equal to 1 - x/n for small x. Here, let x = 0.001 and n = 10, so (0.999)^(1/10) = (1 - 0.001)^(1/10) is approximately 1 - 0.001 / 10 = 1 - 0.0001 = 0.9999.

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