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Boolean Algebra - class-XI
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The conditional $( p \wedge q ) \Rightarrow p$ is
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A
a tautology
💡 Explanation:
Constructing a truth table for (p AND q) => p: if (p AND q) is true, then p must be true. If (p AND q) is false, the implication is vacuously true. Thus, it is a tautology.