Applications of Pascal's Law

It works on the principle of Pascals law.
Pascal's law: Pressure on a confined fluid is transmitted undiminished and acts with equal force on equal areas and at 90 degrees to the container wall.
Uses of hydraulic press - Hydraulic presses are commonly used for forging, clinching, moulding, blanking, punching, deep drawing, and metal forming operations.

Answer is B.
Hydraulics is the use of a liquid under pressure to transfer force or motion, or to increase an applied force. The pressure on a liquid is called HYDRAULIC PRESSURE. And the brakes which are operated by means of hydraulic pressure are called HYDRAULIC BRAKES. These brakes are based on the principle of Pascals law. 
The Pascal law states that 'The pressure exerted anywhere in a mass of confined liquid is transmitted undiminished in all directions throughout the liquid'.

The answer is A.

Pressure is the amount of force acting per unit area. That is, P=F/A.
where:
p is the pressure,
F is the normal force,
A is the area of the surface on contact. Let us consider A = $\pi { r }^{ 2 }$.
Therefore, $\dfrac { { F } _{ 1 } }{ { \pi { r } _{ 1 } }^{ 2 } } =\dfrac { { F } _{ 2 } }{ { \pi { r } _{ 2 } }^{ 2 } } $.

Hydraulic press works on Pascal's principle, which states - “pressure throughout a closed system is constant.” 

hydraulic brakes are based on the pascal`s law and is used for amplifying the applied force to a given extent .

A hydraulic lift is used to lift or support heavy objects. It consists of two pistons of variying cross sectional areas.

A hydraulic press is a mechanical machine used to lift or compress large loads. A hydraulic press consist of two cylinders $C _1$ and $C _2$, fitted with pistons, valves and tubes.

Hydraulic brake confirms to Pascal's law and is used in automobiles. It consist of a master cylinder filled with brake oil and provided with an airtight frictionless piston.

In the construction of hydraulic press, release valve and press foot valves are there.

Hydraulic jacks works on the Pascal's law that the pressure in closed container is the same at all points.

Jacks can be categorized based on mechanical and hydraulic forces.

The shaft in the floor jack is horizontal. Hence option B is correct.

Hydraulic jacks use pump plungers to move oil through two cylinders.

Two types of hydraulic jacks are commonly used- bottle jacks and floor jacks.

Force required        $F = PA$    

Hydraulic jack is a device, works on the Pascal's law, used to lift heavy objects. 

The piston in the master cylinder is connected by mechanical linkage to the Brake pedal in the hydraulic braking system.

Most brakes on cars now are what are called "Power" brakes, and driven by a hydraulic braking control system

$f=900 N$
$a=\pi \times (\frac {1.8}{2})^2=\pi \times \frac {(1.8)^2}{4}$
$A=\pi \times (\frac {36}{2})^2=\pi \times \frac {(36)^2}{4}$
Now $\frac {f}{a}=\frac {F}{A}$
$\Rightarrow \frac {900\times 4}{\pi (1.8)^2}=\frac {F\times 4}{\pi \times (36)^2}$
$\therefore F=\frac {900\times 4}{\pi \times 1.8\times 1.8}\times \frac {\pi \times 36\times 36}{4}$
$=36\times 10^4N$.

$\begin{array}{l} \dfrac { f }{ { 10 } } =\dfrac { { 1000 } }{ { 225 } }  \ f=\dfrac { { 10000 } }{ { 225 } }  \ f=44.44N \end{array}$

The hydraulic machine uses Pascal's principle, which states that states that the pressure exerted anywhere in a confined incompressible fluid is transmitted equally in all directions throughout the fluid.
The hydraulic machine is used to multiple force or to transmit force from one location to another. 
i)     hydraulic brakes
ii)    hydraulic press
ii)    hydraulic lift

We know that $P _{1} = P _{2}$

$\Rightarrow \dfrac{F _{1}}{A _{1}} = \dfrac{F _{2}}{A _{2}} $

$\Rightarrow \dfrac{A _{1}}{A _{2}} = \dfrac{F _{1}}{F _{2}}  = \dfrac{1}{30} $

$\Rightarrow  1:30 $

Answer is A.

Pressure is the amount of force acting per unit area. That is, $P=F/A$.
where:
$p$ is the pressure,
$F$ is the normal force,
$A$ is the area of the surface on contact. Let us consider A = $\pi { r }^{ 2 }$.
Therefore, $\dfrac { { F } _{ 1 } }{ { \pi { r } _{ 1 } }^{ 2 } } =\dfrac { { F } _{ 2 } }{ { \pi { r } _{ 2 } }^{ 2 } } $.
In this case, $\dfrac { 1500 }{ { 20 }^{ 2 } } =\dfrac { W }{ { 1 }^{ 2 } } ,\quad W\quad =\quad 3.75\quad kg.$
Hence, weight to be placed on the small piston sufficient to lift a car of mass 1500 kg is 3.75 kg.

Weight on the ram  $F  =  mg=1000\times 10 = 10000$

Using   $\dfrac{F _1}{A _1} = \dfrac{F _2}{A _2}$

Hydraulic press is used in extraction of oil from oil seeds by crushing.