Converting between fractions or decimals and percentages - class-VIII

Given percent  $={33}\dfrac{1}{3}%$

$12%=\dfrac{12}{100}=\dfrac{3}{25}$

Given, $138 %=.....$

Given, we need to find $ 128 %$

$1.8% $= $\dfrac{1.8}{100} = 0.018$

Number of absent members
= 25 % of 200
= $\displaystyle \frac{25}{100}\times 200=50$

A non-leap year has $= 365$ days

0.9% = $\displaystyle\frac{0.9}{100},=, 0.009$

Let the persons income = $I$
He spends, $33 \frac{1}{3}$ % of his income = $\frac{100}{3}$ %
Thus, Money spend on food = $\frac{100}{3}$ % of I = $\frac{\frac{100}{3}}{100}$ of I = $\frac{I}{3}$

Thus, the man spends $\frac{1}{3}$ of his income on food.

$\frac{1}{8}$ % = $\frac{\frac{1}{8}}{100} = \frac{1}{800}$

$35$ % = $\frac{35}{100}$ = $\frac{7}{20}$

$18$ % = $\dfrac{18}{100}$ = $\dfrac{9}{50}$

$49$% can be written as $\dfrac {49}{100}$

To convert a percent to a fraction, write it over a denominator of 100 and simplify:
$420% = \cfrac{420}{100} = \cfrac{21}{5}$

The fraction of $20%$ is 

Converting a given fraction into simple fraction as:

Let the number be $ x $
So, $ 60 $ $%$ of $ x = 45 $
$ \Rightarrow  \dfrac {60}{100} \times x = 45 $

We need to find value of $1%,\text{of},1%,\text{of},25%,\text{of},1000$

$24\times\dfrac{x}{100}=64$

Remaining height = $\left (192 - \dfrac{125}{2}% of 192 \right ) = $192- 120$ = 72 m$
Required distance (distance covered in second hour) then,
$\dfrac{25}{2}% of\ 72 $= $\dfrac{25 \times 72}{2 \times 100} = 9 m$

Let the price at which the other $30$ kg was bought be Rs. x.
CP of mixture = $\frac{100}{120}\times 18 = 15$
$\frac{2.5}{15 x} = \frac{30}{30}$
$15x=2.5$
Hence, x= Rs. $12.5$

$a%=\dfrac { a }{ 100 } $ in fraction

$a%=\dfrac { a }{ 100 } $ in fraction

$15%$ of $10%$ of $20%$ of $1000$

$5%$ of $600=\dfrac{5}{100}\times 600=5\times 6=30$

For parallel resistances, if each resistance has the same percentage error, the equivalent resistance inherits that same percentage error. With 1/R = 1/R₁ + 1/R₂ + 1/R₃, taking the differential shows that percentage error propagates directly when all resistances have identical % errors.

$;\displaystyle\frac{100}{3\times100}\times,A=\displaystyle\frac{3}{2}\times,B=\displaystyle\frac{1}{8}\times,C=x,(say)$
$;;;;;\Rightarrow;A=3x,,B=\displaystyle\frac{2}{3}x,,C=8x$
$;;;;;;\Rightarrow;A\colon,B\colon,C=3\colon\displaystyle\frac{2}{3}\colon8=9\colon2\colon24$.

Let the original fraction be $\dfrac {p}{q}$. 

Half of $ 1%$ in decimals

Given that : x is $m%$ of y

$0.08%$ can be written as $\dfrac{0.08}{100}$

To convert a percent to a fraction, write it over a denominator of 100 and simplify:
$8% = \cfrac{8}{100} = \cfrac{2}{25}$

$75$%$=\cfrac{75}{100}=\cfrac{3}{4}$

We have, $\sqrt{64%}$

Let the original price of rice be $Rs. x\ per\ kg$.