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Using Decimals in Measurements - Class VII
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A shopkeeper purchased $346$ kg $500$ g of orange. Later on, he found that $109$ kg $300$ g of oranges were rotten. Find the quantity of oranges in good condition.
AnswerClick to flip back
A
$237$ kg $200$ g
💡 Explanation:
We know that $gram$ is abbreviated as $gm$
$1$ $kg =1000$ $gram$
Total weight of Oranges purchased $ = B = $ $346$ $kg$ $500$ $gm$
Total weight of rotten oranges $=A = $ $109$ $kg$ $300$ $gm$
(i) We have to subtract $109\ kg$ $300\ gm$ from $346$ $kg$ $500$ $gm$ to get the weight of good conditioned oranges
$109$ $kg$ $300$ $gm$ $ = 109kg + 300gm$ $=A $ ...................(1)
$346$ $kg$ $500$ $gm$ $ = 346kg + 500gm$ $=B $ ...................(2)
$B-A = [346\ kg+500\ gm]-[109\ kg +300\ gm]$
$ = [346\ kg-109\ kg] + $ $[500$ $gm$ $-$ $300$ $gm$]
$= 237 $ $kg $ $+ $ $200$ $gm$
Therefore, $237 $ $kg $ $200$ $gm$ of oranges are in good condition.